Let f and b be the cost of foil and batteries respectively. We are first given that:
2f+3b=21 subtract 3b from both sides
2f=21-3b divide both sides by 2
f=(21-3b)/2
Then we are given:
5f+2b=25, using f found above in this equation gives you:
5(21-3b)/2+2b=25
(5(21-3b)+4b)/2=25 multiply both sides by 2
5(21-3b)+4b=50 carry out indicated operations on left side
105-15b+4b=50 combine like terms on left side
105-11b=50 subtract 105 from both sides
-11b=-55 divide both sides by -11
b=5, since f=(21-3b)/2
f=(21-3*5)/2
f=3
So batteries cost $5 and foil cost $3.
Answer:-28
Step-by-step explanation:
Answer:
(3, - 25 )
Step-by-step explanation:
Given a quadratic in standard form : y = ax² + bx + c : a ≠ 0
The the x- coordinate of the turning point is
x = - 
Given
y = (x + 2)(x - 8) ← expand factors using FOIL
= x² - 6x - 16 ← in standard form
with a = 1 and b = - 6, thus
x = -
= 3
Substitute x = 3 into the equation for corresponding value of y
y = (3 + 2)(3 - 8) = 5(- 5) = - 25
turning point at (3, - 25 )
Answer:
Yes, 88 is the solution
Step-by-step explanation:
1/8x = 11
Multiply both sides by 8
8(1/8)x = 11 (8)
x = 88