Answer:

Step-by-step explanation:
If k items out of 20 total items are defective, then the number of non-defective item is 20 – k. The probability of choosing 5 items where all of them are non-defective is
- For the 1st slot the chance is (20 – k)/20
- For the 2nd slot the chance is (20-k-1)/(20-1) = (19-k)/19
- For the 3rd slot: (18 – k)/18
- 4th : (17 – k)/17
- 5th: (16 – k)/16
The probability in total would be

So the probability of selecting at least 1 defective item is the inverse of this, which is

Answer:
60 weeks
Step-by-step explanation:
Factor both numbers 12 and 15:
Find LCM(12,15). The common factor is only 3, multiply ths common factor by all factors that remain. Then

This means that the fewest number of weeks that will pass before both machines are cleaned again in the same week is 60 weeks.
Length of x is 98.2 m
<u>Step-by-step explanation:</u>
Step 1:
Use the trigonometric ratio tan 27° to find the common side of both the right angled triangles.
tan 27° = opposite side/adjacent side = opposite side/9
∴ Opposite side = 9 tan 27° = 9 × - 3.27 = -29.46 m
Step 2:
Use this side and trigonometric ratio cosine to find the value of x.
cos 49° = adjacent side/x = -29.46/x
∴ x = -29.46/cos 49° = -29.46/0.30
= 98.2 m (negative value neglected)
Point slope form : y-y1 = m(x-x1)
slope intercept form : m=(y-y1)/(x-x1)
standard form : Ax + By = C
just pick any random points on a graph and plug the same points into all three forms.