Using the probability and odds concepts, it is found that the odds against it containing a number greater than or equal to 7 is
.
- A probability is the <u>number of desired outcomes divided by the number of total outcomes</u>.
- An odd is the <u>number of desired outcomes divided by the number of non-desired outcomes</u>.
In the rack, there are 15 balls, numbered from 1 to 15. Of those, <u>6 are less than 7</u>(against it containing a number greater than or equal to 7 is equivalent to it containing a number less than 7), thus:
- There are 6 desired outcomes.
- There are 9 non-desired outcomes.
The odd is:

The odds against it containing a number greater than or equal to 7 is
.
A similar problem is given at brainly.com/question/21094006
It is true since you’re multiplying the same number on both the sides
1.) -8 + 10(6 + 4r)
First multiply the 10 into (6 + 4r)
-8 + 60 + 40r
52 + 40r
2.) (8m² - 8m + 8) - (2m - 7m² - 6)
Distribute the - into (2m - 7m² - 6)
8m² - 8m + 8 - 2m + 7m² + 6
Combine like terms
15m² - 10m + 14
(idk if you need to factor this or if you can leave it as is)
Answer:
Is D
Step-by-step explanation:
Because is moving four times right and four times down.
Answer:
5083
Step-by-step explanation:
6^3 + 5(8 + 15)
Simplify the bracket first
6 x 6 x 6 + 5 (23)
216 + 5 (23)
221 (23)
221 x 23 = 5083