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r-ruslan [8.4K]
4 years ago
8

The girls decide to only spend $40 between them.on average,how much money can each girl spend?

Mathematics
1 answer:
Neko [114]4 years ago
3 0
20 I think idk I'm doing this for points
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en una reunion hay 2 arequipeños,2 trujillanos, 3 piuranos y 4 limeños ¿de cuantas maneras diferentes pueden colocarse en un fil
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In a meeting there are 2 Arequipeños, 2 Trujillanos, 3 Piuranos and 4 Limans. In how many different ways can they be placed in a row so that those of the same city are together?

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4 years ago
A survey of 25 randomly selected customers found the ages shown (in years). The mean is 32.64 years and the standard deviation i
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Answer:

See below for answers and explanations

Step-by-step explanation:

<u>Part A</u>

Assuming that conditions have been met for the interval, we use the formula \displaystyle CI=\bar{x}\pm t\frac{s}{\sqrt{n}} where \bar{x} represents the sample mean, t represents the critical value, s represents the sample standard deviation, and n is the sample size.

The critical value of t for an 80% confidence level with degrees of freedom df=n-1=25-1=24 is equivalent to t=1.317836

Thus, we can compute the confidence interval:

\displaystyle CI=\bar{x}\pm t\frac{s}{\sqrt{n}}\\\\CI=32.64\pm1.317836\biggr(\frac{9.39}{\sqrt{25}}\biggr)\\\\CI\approx\{30.17,35.11\}

Therefore, we are 80% confident that the true mean age of all customers is between 30.17 and 35.11 years.

<u>Part B</u>

The margin of error is \displaystyle t\frac{s}{\sqrt{n}}=1.317836\biggr(\frac{9.39}{\sqrt{25}}\biggr)\approx2.47

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3 years ago
Anyone know the answers?? Please help?
Murljashka [212]
24. C
25. D

I honestly don't know.
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