Answer:
The 80% confidence interval for the mean consumption of meat among people over age 23 is between 4 and 4.2 pounds.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find M as such
In which 
is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the mean subtracted by M. So it is 4.1 - 0.07 = 4.03 pounds
The upper end of the interval is the mean added to M. So it is 4.1 + 0.07 = 4.17 pounds
Rounded to one decimal place
The 80% confidence interval for the mean consumption of meat among people over age 23 is between 4 and 4.2 pounds.
Answer:
27 tiles
Step-by-step explanation:
Here is the complete question :
Todd uses 21 white tiles and some black tiles to make a mosaic.the mosaic has a total area of 144 square centimeters. Each tile has an area of 3 square centimeters. How many black tiles did Todd use
<u><em>Steps to take to determine the answer</em></u>
- Determine the total area of the white tiles used. This can be determined by multiplying the number of white tiles by the area of a tile
- subtract the area of the white tiles from the total area of the mosaic.
- Divide the answer derived in the previous step by 3
Area of the white tile = area of each tile x total white tiles used
3 x 21 = 63cm²
144cm² - 63cm² = 81cm²
Number of black tiles used = 81cm² / 3cm² = 27 tiles
The answer for 32% of 50 is 16.
Answer:
x=4
Step-by-step explanation:
f(x) = (x-2)^5 +3
Let f(x) = 35
35 = (x-2)^5 +3
Subtract 3 from each side
35-3 = (x-2)^5 +3-3
32 = (x-2)^5
Take the fifth root of each side
32 ^ (1/5) = (x-2)^5^ 1/5
2 = x-2
Add 2 to each side
2 +2 = x-2+2
4 =x
Let 
be the number of liters of the 10% solution to be used, and 
the number of liters of the 4% solution. The chemist wants to end up with a 4 liter solution, so
For each liter used in the mixture, a concentration of either 10% or 4% acid will be contributed, and the goal is to make a 4L solution whose concentration is 7%, which means
Solving for 
gives 
, so 2L of both solutions is needed.
