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Kazeer [188]
4 years ago
10

Solve for x. ln(3x+2)=4

Mathematics
1 answer:
Thepotemich [5.8K]4 years ago
7 0

The value of x in ln(3x + 2) = 4 is \bold{\frac{e^{4} - 2}{3}}

<u>Answer:</u>

Option a

<u>Solution:</u>

From question, given that ln(3x + 2) = 4

ln(3x + 2) = 4 ----- eqn 1

By raising “e” to the power of both sides of equation, the above equation becomes

e^{\ln (3 x + 2)} = e^{4}

“ln” and “e” cancel out each other in left hand side of above equation. Hence we get  

3x + 2 = e^{4}

Rearranging the terms, the above equation becomes,

3 x=e^{4}-1

x = \frac{e^{4} - 2}{3}

Thus the value of x in ln(3x + 2) = 4 is \bold{\frac{e^{4} - 2}{3}}

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The graph of the line 4x+3y= 12 is translated right 1 unit and down 3 units. What is the equation of the new line?
ruslelena [56]

Answer: y = 7/3 - (4/3)*x

Step-by-step explanation:

First, let's write our line in the notation:

y = f(x)

So we must isolate y in the equation:

4x + 3y = 12

3y = 12 - 4x

y = 12/3 - (4/3)*x = 4 - (4/3)*x

Now, we have two translations, one horizontal and one vertical.

Let's define them in general cases:

Horizontal translation.

When we have y = f(x) and we want to do a horizontal translation of A units to the right (A positive) we have:

y = g(x) = f(x - A)

So we replace our variable x by x - A.

Vertical translation.

When we have y = f(x) and we want to do a horizontal translation of A units up (A positive) we have:

y = g(x) = f(x) + A.

Then in this case we have:

y = f(x) = 4 - (4/3)*x

then, the horizontal translation of 1 unit to the right is:

y = f(x - 1) = 4 - (4/3)*(x - 1)

And the translation of 3 units down (a vertical translation) is:

y = f(x - 1) - 3 = 4 - (4/3)*(x - 1) - 3  = 1 + 4/3 - (4/3)*x

y = 7/3 - (4/3)*x

This equation represents the new line.

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4 years ago
GEOMETRY HELP? Circle O is shown below. What is the measure of BAC?
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4 0
3 years ago
Read 2 more answers
How do i solve 5x+3y=-10 &amp; 3x+5y=-6​
Gre4nikov [31]
Solve it using elimination method:

5x+3y=-10
3x+5y=-6

Essentially what you would want to do is eliminate a variable so you have to multiply the two equations so that the two “y”s cancel each other out. You do this by multiplying one by a negative number and the other one a positive number. Doesn’t matter what number you multiply the number with; however, both numbers need to be the same distance away from zero. Also, if you’re going to multiply one term, then all the terms will need to be multiplied.

-5(5x+3y)=-10
3(3x+5y)=-6

Distribute and Multiply:
-25x-15y=50
9x+15y=-18

Now add the two equations by adding the x’s together, y’s, and the total.

The y’s end up canceling each other.

-16x=32

Divide:

X=-2

Now that you have “X” substitute x from one of the equations from the beginning. You may do two for checking answers.

3(-2)+5y=-6

-6+5y=-6

5y=0

Y=0

The answer is:
x=-2
y=0

(-2,0)

7 0
3 years ago
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