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Ludmilka [50]
4 years ago
9

Solve 2 log 2x=4, round to nearest Thousandth

Mathematics
1 answer:
tekilochka [14]4 years ago
5 0
X=50 x > 0
2log10(2x)=4
determine the defined range
2log10(2x)=4 x > 0
divide both sides by 2
log10(2x)=2
solve by converting the logarithm to exponential form
2x=10 to the second power
2x=100
divide both by two
x=50
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3 years ago
Can anyone help with this <br> 35=11x <br> Can you do a step by step too<br><br> Thanks!
EastWind [94]

Answer:

x = \frac{35}{11}

Step-by-step explanation:

Given

35 = 11x ( isolate x by dividing both sides by 11 )

\frac{35}{11} = x

8 0
4 years ago
PLEASE HELP!! What is the value of x?
Black_prince [1.1K]
To find x, first we'll split the triangle in two right triangles.

The first triangle will be the one with sides (8,x+4,y) and the second triangle will be the one with sides (12,2x+1,y).

As you can see, these two triangles share the side 'y'.

To solve we'll do the following; first solve for 'y' by applying the Pythagorean theorem in the second triangle, and finally solve for 'x' applying Pythagorean theorem in the first triangle.

From the second triangle (12,2x+1,y) we solve for 'y' by writing:
y^{2}=12^{2}- (2x+1)^{2}=144-4 x^{2} -4x-1=

Now that we know 'y^2' we apply Pythagorean Theorem in the first triangle (8,x+4,y)
8^{2}= (x+4)^{2}+ y^{2}= (x^{2}+8x+16)+(143-4 x^{2} -4x)
64=159-3 x^{2} +4x

Now you solve the quadratic equation, you'll get a positive and negative value; as this are lengths, you take the positive and get:

x= \frac{19}{3}



5 0
4 years ago
Line A passes through the coordinate points (-2/5,0) and (0,1). Which of the following lines will line A never intersect? ​
expeople1 [14]

Answer:

Option B

Step-by-step explanation:

Only lines which are parallel to the line which connects the given two points will neve r intersect,

parallel line has same slope

the slope of the line which connects the given two points is, 5/2

and the line is option B also has the same slope, so those two lines will never intersect each other.

Answered by GAUTHMATH

4 0
3 years ago
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