take a factor of 6 out to make 6(4x-3)
Answer:
x = 75°
Reason:
m∠EFG and m∠ABC are supplementary angles
We have been given a quadratic function
and we need to restrict the domain such that it becomes a one to one function.
We know that vertex of this quadratic function occurs at (5,2).
Further, we know that range of this function is
.
If we restrict the domain of this function to either
or
, it will become one to one function.
Let us know find its inverse.

Upon interchanging x and y, we get:

Let us now solve this function for y.

Hence, the inverse function would be
if we restrict the domain of original function to
and the inverse function would be
if we restrict the domain to
.
She used 10 more gallons of green paint
Hope this helps if it does yourwelcome
The missing values are 28° and 62°
<h3>What are perpendicular lines?</h3>
Perpendicular lines are said to be two lines that intersect or meet each other at right angles, that is 90 degrees.
From the information given, we have that;
Line AC ⊥ Line BE
Where:
- m ∠ ADE = (x + 5)°
- m ∠ DBE = (3x - 7)°
Hence,
x + 5 + 3x - 7 = 90
collect like terms
4x = 90 + 2
4x = 92
Make 'x' the subject
x = 92/ 4
x = 23
For the missing values
m ∠ ADE = (x + 5)° = ( 23 + 5) = 28°
m ∠ DBE = (3x - 7)° = (3(23) - 7) = 62°
Thus, the missing values are 28° and 62°
Learn more about perpendicular lines here:
brainly.com/question/17683061
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