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MA_775_DIABLO [31]
3 years ago
11

Write the slope-intercept form of the given line. Include your work in your final answer. Type your answer in the box provided o

r use the upload option to submit your solution.

Mathematics
2 answers:
Nitella [24]3 years ago
8 0

Answer:

The slope intercept form is y=\frac{-1}{3}x+1.

Step-by-step explanation:

Consider the provided graph.

The slope intercept form is:

y=mx+c

Where <em>m</em> is slope of the line and <em>c</em> is <em>y</em> intercept.

From the provided graph it is clear that the line intersect the <em>y</em> axis at (0,1).

Thus, the value of <em>c</em> is 1.

By observing the graph it is clear that the <em>x</em> intercept are (3,0).

Use two point slope formula to find the slope of the graph:

m=\frac{y_2-y_1}{x_2-x_1}

Substitute y_2=0, y_1=1,x_2=3 \text{and}\ x_1=0 in the above formula.

m=\frac{0-1}{3-0}

m=\frac{-1}{3}

Therefore, the slope of the line is \frac{-1}{3}

Substitute the value of <em>m</em> and <em>c</em> in slope intercept form.

y=\frac{-1}{3}x+1

Hence, the slope intercept form is y=\frac{-1}{3}x+1.

laila [671]3 years ago
6 0
(Is it this one?)

y = mx + b 
m is the slope and b is the y intercept.

The line is passing through the y-axis at 1, so you know b will be 1.

To find the slope, look at the line and see where it touches the corners of the squares perfectly. It touches them perfectly at (0, 1) and (3, 0). Use the slope formula to find the slope: \frac{x2 - x1}{y2 - y1}.

\frac{x2 - x1}{y2 - y1} ⇒ \frac{0 - 1}{3 - 0} = \frac{-1}{3}

The slope is -1/3.
Now you know that m is -1/3.

Plug the slope & y intercept into the equation: y = mx + b

y = -1/3x + 1 is the slope-intercept form of the line.
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Answer:

An equation that represents the given situation is 203+x=250 and the additional number of students that can be seated is 47

Step-by-step explanation:

Number of students already seated in school cafeteria = 203

Let x be the additional number of students that can be seated

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So, 203+x=250

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Hence an equation that represents the given situation is 203+x=250 and the additional number of students that can be seated is 47

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