I would use the pythagorean theorem to find the lengths of each side. a² + b² = c².
Side AB is one we're looking for. If you make other right triangle with that same side you can see that one length is 4 and the other is 3. So, 4² + 3² = c² → 25 = c² → 5 = c. Side AB is length 5.
Side AC is another. Do the same with that side and you get that one length is 4 and the other is 3. (This is the same one as above) so side AC is length 5.
Side BC is the last one. One of the lengths is 1 and the other is 1 → 1² + 1² = c² → 2 = c² → 1.414213562 = c so side BC is approximately length 1.41.
Add each length up and you get a perimeter of roughly 11.4
Answer:
ab • (11a + b + 1) If its not im really sorry
Step-by-step explanation:
STEP one
(((((3•(a2))•b)+5ab)-4ab)+(a•(b2)))+(23a2•b)
STEP Two
((((3a2 • b) + 5ab) - 4ab) + ab2) + 23a2b
STEP 3
STEP 4
Pulling out like terms
4.1 Pull out like factors :
11a2b + ab2 + ab = ab • (11a + b + 1)
I’m doing this so I can ask a question
