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mihalych1998 [28]
3 years ago
9

Which linear inequality is represented by the graph? y ≤ 1/2x + 2 y ≥ 1/2x + 2 y ≤ 2/3x + 2 y ≥ 2/3x + 2

Mathematics
2 answers:
Arturiano [62]3 years ago
8 0

Here Go The Picture

patriot [66]3 years ago
6 0
Post the graph and I can help
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How many units long is a segment whose endpoints are (2,3) and (7,15)?
Ahat [919]

Answer:

13 units

Step-by-step explanation:

Distance formula: d = \sqrt{(x2-x1)^2 + (y2-y1)^2}

Simply plug in your variables

d = \sqrt{(7-2)^2 + (15-3)^2}

d = \sqrt{5^2 + 12^2}

d = \sqrt{25 + 144}

d = \sqrt{169}

d = 13

5 0
3 years ago
Explain it so I can better understand it
lorasvet [3.4K]
The question is essentially asking who's equation works better (Part A) and to explain why (Part B). 
Marcella is suggesting the equation 6r + 12 = 683.88 
Julia is suggesting the equation 6(r + 12) = 683.88 

Six people are on the trip.
It is $12 PER person to rent a floatation device. 
The total cost of the trip was $683.88.

Hope I've helped!


6 0
3 years ago
CAN YOU HELP ME!
Nat2105 [25]

Answer:

B) 15/(9+(-9))

Step-by-step explanation:

Be careful of the parentheses because if you just write out 15/9+(-9),

it's technically, saying that 15/9+(-9)=5/3+(-9)=5/3-9, and that's different from what you want to express, mathematically.

3 0
2 years ago
Determine the currents in the picture
Elenna [48]

Answer:

The value of currents are I_1=0A, I_2=1A and I_3=1A.

Step-by-step explanation:


The Ohm's law states that

V=IR

it is given that the V₁=3V and V₂=4V.

In a parallel circuit:

  • Voltage is same in each component
  • Sum of the currents equals to the total current that flows.

I_2=I_1+I_3                   .... (1)

Equation for first loop is,

V_1=4I_1+3I_2

3=4I_1+3I_2              ..... (2)

Equation for second loop is,

V_2=1I_3+3I_2

4=1I_3+3I_2             ..... (3)

On solving (1), (2) and (3) we get

I_1=0


I_2=1

I_3=1

Therefore the value of currents are I_1=0A, I_2=1A and I_3=1A.

6 0
3 years ago
If m∠OZQ = 125 and m∠OZP = 62, what is m∠PZQ
const2013 [10]

Answer:

<h2>               63° or  173°</h2>

Step-by-step explanation:

You didn't specify where the point P is so there are two posibilites:

1.

P₁Z is dividing angle OZQ

then:

      m∠P₁ZQ = m∠OZQ - m∠OZP₁ = 125° - 62° = 63°

2.

P₂Z is outside angle OZQ

then

    m∠P₂ZQ = 360° - (m∠OZQ + m∠OZP₂) = 360° - (125° + 62°) = 173°

5 0
3 years ago
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