If (x/3)-1 is twice as large as (x/4)-3, what is the value of x?
2 answers:
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Answer:
see explanation↓
Step-by-step explanation:
(a)
ANSWER: Linear binomial
(b)
ANSWER: Quadratic trinomial
(c)
ANSWER: Linear binomial
(d)
ANSWER: Quadratic trinomial
(e)
ANSWER: Quadratic binomial
we are given
f(x)=[x=1]
where bracket means ceiling functions
we know that
Ceiling function returns the least value of the integer that is greater than or equal to the specified number
so, we can check each options
option-A:
At x=-4:
f(x)=[-4-1] =-5
For x<-3:
Let's assume
x=-3.1
f(x)=[-3.1-1] =[-4.1]=-5
so, this interval is TRUE
option-B:
At x=-2:
f(x)=[-2-1] =-3
For x<-1:
Let's assume
x=-1.1
f(x)=[-1.1-1] =[-2.1]=-3
so, this is FALSE