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2 years ago

If (x/3)-1 is twice as large as (x/4)-3, what is the value of x?

Mathematics

2 answers:

Ganezh [65]2 years ago

7 0

Answer:

Step-by-step explanation:

Angelina_Jolie [31]2 years ago

3 0

Answer:

x = 30

Step-by-step explanation:

The equation modelling the statement is

$\frac{x}{3}$ - 1 = 2 ( $\frac{x}{4}$ - 3 ) ← distribute parenthesis by 2

$\frac{x}{3}$ - 1 = $\frac{x}{2}$ - 6 ( multiply through by 6 to clear the fractions )

2x - 6 = 3x - 36 ( subtract 2x from both sides )

- 6 = x - 36 ( add 36 to both sides )

30 = x

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scoray [572]

Solution:

The difference of cubes identity is

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I will show you , how this identity is valid.

Taking R H S

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3 years ago

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What is the solution to the equation below?

Hitman42 [59]

The answer is B).762

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2 years ago

Solve for x.<br> (x - 3)^2 -10 = 15

Brut [27]

Answer:

Step-by-step explanation:

Let's go:

$(x - 3)^2 - 10 = 15 \\\ (x - 3)^2 = 15 + 10 \\\ (x - 3)^2 = 25 \\\ x - 3 = \sqrt{25} \\\ x - 3 = \pm 5$

Solution #1:

x - 3 = 5

x = 5 + 3

x = 8

Solution #2:

x - 3 = - 5

x = - 5 + 3

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I hope I helped you.

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2 years ago

-5/8 Times 2/3 as a fraction

lys-0071 [83]

The answer to your question is -5/12. I hope this helps!

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DiKsa [7]

Answer:

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Step-by-step explanation:

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