If (x/3)-1 is twice as large as (x/4)-3, what is the value of x?

Mathematics

2 answers:

Ganezh [65]3 years ago

7 0

Answer:

Step-by-step explanation:

Angelina_Jolie [31]3 years ago

3 0

Answer:

x = 30

Step-by-step explanation:

The equation modelling the statement is

$\frac{x}{3}$ - 1 = 2 ( $\frac{x}{4}$ - 3 ) ← distribute parenthesis by 2

$\frac{x}{3}$ - 1 = $\frac{x}{2}$ - 6 ( multiply through by 6 to clear the fractions )

2x - 6 = 3x - 36 ( subtract 2x from both sides )

- 6 = x - 36 ( add 36 to both sides )

30 = x

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