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Dovator [93]
3 years ago
12

A certain species of alligators is to be introducers into a swamp, and wildlife experts estimate the population will grow to P(t

)=(803)3^t/3, where t represents the number of years from the time of introduction. what is the tripling time for this population of alligators
Mathematics
2 answers:
Effectus [21]3 years ago
7 0

Answer:

3 years

Step-by-step explanation:

P(t)=803 X 3^{t/3}

First, we determine the initial population.

At t=0

P(0)=803 X 3^{0/3}

P(0)=803

For the initial population to triple.

P(t)=3P(0) = 3 X 803 = 2409

P(t)=803 X 3^{t/3}

2409=803 X 3^{t/3}

\frac{2409}{803}= 3^{t/3}

3= 3^{t/3}

Since the bases are equal

\frac{t}{3}=1

t=3

In 3 years, the population of the alligators will be triple its population at introduction.

Phoenix [80]3 years ago
6 0

Answer:

3 years

Step-by-step explanation:

Note that:

P(0) = 803

So Tripling time  ==>  P(t) = 3*P(0) = 3*803 = 2409

Then we have an equation:

2409  = 803*3^{\frac{t}{3} }

<=> 3 = 3^{\frac{t}{3} }  

<=> 1 = \frac{t}{3}

<=> t = 3

So the tripling time for this population of alligators is 3 years

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<span><span><span>dA</span><span>dt</span></span>=<span>(l)</span><span>(<span><span>dw</span><span>dt</span></span>)</span>+<span>(<span><span>dl</span><span>dt</span></span>)</span><span>(w)</span></span>

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8 0
3 years ago
Solve the following subtraction problems.<br> a. 8 mi 133 yd 2 ft – 5 mi 107 yd 2 ft
beks73 [17]

<u>Answer:</u>

3 miles 26 yards

<u>Step-by-step explanation:</u>

We are to perform subtraction on the following:

8 mi 133 yd 2 ft – 5 mi 107 yd 2 ft

We have to divide the amount of miles from miles, yards from yards and feet from feet. So a good idea is to write it this way in order to avoid any confusion:

   8 mi 133 yd 2 ft

-   5 mi 107 yd 2 ft

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So we are left with 3 miles 26 yards.

8 0
3 years ago
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PilotLPTM [1.2K]
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6 0
3 years ago
Given trapezoid abcd with bases ab and cd, draw diagonals ac and bd. let e be the midpoint of ac and f the midpoint of bd. prove
mylen [45]
Consider the picture.

Let MN be the midsegment of the trapezoid.

That is M is the midpoint of AD, N is the midpoint of BC.

Being the midsegment of the trapezoid, MN is parallel to the bases.


Let O and K be the intersections of the diagonals with the midsegment.




MN//AB, so MO//AB, and since M is the midpoint of DA, O must be the midpoint of DB, 

Similarly we prove that K is the midpoint of CA.

Thus O is F and K is E.

O and K lie on the midsegment MN, so F and E lie on the midsegment.



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7 0
4 years ago
Please help really important for my grade :(
Licemer1 [7]

Answer:

≈ 50.7 cm²

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The area (A) of Δ XYZ is calculated as

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