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2 years ago

pls help, no rush I just get really stressed when I don't know the answer to a problem, pls explain ur reasons :)

Mathematics

1 answer:

gtnhenbr [62]2 years ago

3 0

9514 1404 393

Answer:

2. correct

3. addition property of equality

4. substitution property of equality

Step-by-step explanation:

You're asked for the Reasons, so you need to examine the Statements to see how you get from one line to the next.

The first line of Statement 2 differs from Statement 3 in that m∠GHI has been added to both sides of the equation (ignoring the typo in statement 3). The reason you can add the same thing to both sides of an equation is given by the <em>Addition Property of Equality</em>.

Statement 3 differs from Statement 4 in that one of the m∠GHI has been replaced by m∠JKL. We can do this replacement because those measures are equal to each other. Replacement of equals by equals is allowed by the <em>Substitution Property of Equality</em>.

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What is the justification for each step in the solution of the equation?

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2 years ago

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Solve 58 - 10x s 20 + 9x.

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Step-by-step explanation:

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2 years ago

Can someone plz help me solved this problem I need help ASAP plz help me! Will mark you as brainiest!

miv72 [106K]

Answer:

-1, 1

13, 15

Step-by-step explanation:

x and x+2 are the integers

x*(x+2)= 7(x+x+2) -1
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2 years ago

Test the claim that the mean GPA of night students is larger than 3.1 at the .10 significance level. The null and alternative hy

Alborosie

Answer:

H 0 : μ = 3.1 H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

$t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66$

$df = n-1=75-1 =74$

The p value is:

$p_v = P(t_{74} >8.66) =3.65x10^{-13}$

The significance level is: 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

Step-by-step explanation:

For this case we want to test the claim that mean GPA of night students is larger than 3.1 at the .10 significance level. The claim needs to be on the alternative hypothesis so then we have the following system of hypothesis:

H 0 : μ = 3.1 H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

We have the following info given:

$\bar X = 3.13 , s =0.03 , n =75$

The statistic to check the hypothesis is given by:

$t = \frac{\bar X -\mu}{\frac{s}{\sqrt{n}}}$

Replacing the info given we got:

$t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66$

The degrees of freedom are given by:

$df = n-1=75-1 =74$

The p value since is a right tailed ted is given by:

$p_v = P(t_{74} >8.66) =3.65x10^{-13}$

The significance level is 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

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2 years ago

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