Question

In a study by the Texas A & M University, found there were 23,000 prairie dogs in Texas in 2000. By 2010, the number has increased to 40,000. The exponential growth function D=2.3e^kt describes the prairie dog population, D in ten thousands, t years after 2000.
A) solve for k
B)by this model how many prairie dogs existed last year?
C)in which year will the population double?
PLEASE HELP!

Answer 1

let x=k

D=dog

T=Taxes

I=increase P=population

solve k

d=23,000

t=2000

d=2.3e^

divide both sides by 2

after year is,2000+k2-2.3

=1.999.7

k2- 23,000=

k-x

or

k2-2