Answer: independent variables cause the effect measured in the dependent variables
Step-by-step explanation: In a causal - comparative study, the dependent variables refers to the variable whose changes is being measured or observed. The changes or alteration of the dependent variable is induced by the different values of the independent variable. In causal - comparative study, the different independent variables is assumed to have a direct impact on the output or values of the dependent variable which is measured by the experimenter. Therefore, the independent variable does not change, but causes the observed changes noticed in the dependent variable.
Answer:
91.2
Step-by-step explanation:
add to both sides 15.2 so 76+15.2=91.2
9.3342meters because you convert 2350mm into m which is 2.35m, + and also convert 3.42cm to m which is 0.0342 then + 1.45m +11/2m= 9.3342m
Answer:
Step-by-step explanation:
I don't think this can be done without the diagram. You do not know what HD is opposite. I will take a guess that it is opposite TU which makes TU = 220 because both H and D are midpoints and that makes TU twice as large as HD.
If this is incorrect, post the diagram.
<span>1. Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats.
What is the theoretical probability that the family has two dogs or two cats?
25% chance
</span><span>2. Describe how to use two coins to simulate which two pets the family has.
</span>
You could use the coins to simulate which pet the family has by flipping them and having head be dog and tails be cat (or vice-versa).
<span>3. Flip both coins 50 times and record your data in a table like the one below.
</span><span>Based on your data, what is the experimental probability that the family has two dogs or two cats?
</span>
Based on the results, I concluded that for Heads, Heads (which could be dogs or cats) there was a 24% chance and for Tails, Tails there was a 26% chance
<span>4. If the family has three pets, what is the theoretical probability that they have three dogs or three cats?
1/8 chance (accidentally messed up there) or 12.5%
</span><span>5. How could you change the simulation to generate data for three pets?
</span><span>
To flip 3 coins and add more spots on the chart.
I hope that this helps because it took a while to write out. If it does, please rate as Brainliest
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