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3 years ago

Karolina Bravo

Mathematics

2 answers:

oee [108]3 years ago

7 0

Answer:

The Answer would be 8.

Step-by-step explanation:

9 x 8 = 72

leonid [27]3 years ago

5 0

Answer:

Step-by-step explanation:

72/9 = 8

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Finding first six terms of a sequence

Jlenok [28]

2, 4, 6, 8, 10, 12

difference is 2

6 0

3 years ago

Read 2 more answers

Find the values of the pronumerals in this diagram. Write down the reason in each case.

timofeeve [1]

Answer:

see explanation

Step-by-step explanation:

a and 85 form a straight angle and are supplementary, thus

a + 85 = 180 ( subtract 85 from both sides )

a = 95

b and 85 are vertical angles and are congruent, thus

b = 85

c and 85 are corresponding angles and congruent, thus

c = 85

c and d are vertical angles and congruent, thus

d = 85

In conclusion

a = 95, b = 85, c = 85, d = 85

5 0

3 years ago

What is the coefficient of the x^5y^5- term in the biomial expansion of (2x-3y)^10

jasenka [17]

<u>Answer:</u>

The coefficient of $x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552$

<u>Solution: </u>

The given expression is $(2 x-3 y)^{10}$

As per binomial theorem, we know,

$(x+y)^{n}=\sum n C_{k} x^{n-k} y^{k}$

Now here a = 2x, b = (- 3y) and n = 10 and k = 0,1,2,….10

Now $x^{5}\times y^5$ will be the 6 term where k =5

Now, $\mathrm{T}_{6}=10 \mathrm{C}_{5} \times(2 \mathrm{x})^{(10-5)} \times(-3 \mathrm{y})^{5}=10 \mathrm{C}_{5} 2^{5} \times \mathrm{x}^{5} \times(-3)^{5} \times \mathrm{y}^{5}$

So, the coefficient of $x^{5} \times y^{5} \text { is }=10\left(5 \times 2^{5} \times(-3)^{5}\right$ .

$10 \mathrm{C}_{5}=\frac{10 !}{5 ! \times(10-5) !}=\frac{10 !}{5 !+5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 !}{5 ! \times 5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2 \times 1}=\left(\frac{30240}{120}\right)=252$