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3 years ago

A cd usually sells for $12.00. If the cd is 10% off, and sales tax is 5%, what is the total price of the cd, including tax?

Mathematics

1 answer:

Kazeer [188]3 years ago

5 0

Answer:

$11.34 Discounted Price Including Tax

Step-by-step explanation:

CD is $12.00

10 percent off of 12 dollars is:

12 x .10 = $1.2

12 - 1.2 = $10.8 WITHOUT TAX!!

5/100 = 0.05

0.05 x 10.8 = .54 (Tax itself)

10.8 (Discounted price) + .54 (Tax) = $11.34 Discounted Price Including Tax

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3 years ago

This figure is made up of a quadrilateral and a semicircle.

Arturiano [62]

Answer:

The correct option is B. The area of the figure is 40.4 units².

Step-by-step explanation:

The line AB divides the figure in two parts one is a rectangle and another is semicircle.

The distance formula is

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The length of AB is

$AB=\sqrt{(2+3)^2+(4-2)^2}=\sqrt{25+4}=\sqrt{29}$

The length of AD is

$AD=\sqrt{(-1+3)^2+(-3-2)^2}=\sqrt{4+25}=\sqrt{29}$

Since AB=AD, therefore ABCD is a square. The area of the of square is

$A_1=a\times a=\sqrt{29}\times \sqrt{29} =29$

The area of square is 29 units².

The area of a semicircle is

$A_2=\frac{\pi}{2}r^2$

Since AB is the diameter of the semicircle, therefore the radius of the semicircle is

$r=\frac{d}{2}=\frac{\sqrt{29}}{2}$

The area of the semicircle is

$A_2=\frac{3.14}{2}(\frac{\sqrt{29}}{2})^2=40.3825$

The area of the figure is

$A=A_1+A_2=29+11.2825=40.3825\approx 40.4$

Therefore the area of the figure is 40.4 units². Option B is correct.

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3 years ago

9. Simplify: 6√18+3√50

sukhopar [10]

$6 \sqrt{18} +3 \sqrt{50} =6 \sqrt{9*2} +3 \sqrt{25*2} =6*3 \sqrt{2} +3*5 \sqrt{2}$ =18 sqrt2+15 sqrt2=33 sqrt 2

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3 years ago

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Charra [1.4K]

I think it is possibly point b

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2 years ago

Find the area of each figure. Pls, this is urgent, I will award brainliest.

Crazy boy [7]

Answer:

The area of the figure is;

A = 2,112 in²

Step-by-step explanation:

The given figure is a composite figure consisting of a rectangle AINE and a triangle AIL

The dimensions of the rectangle AINE are;

Length, L = 48 in.

Height, h = 32 in.

The area of the rectangle AINE, A₁ = Length, L × Height, h

∴ A = L × h = 48 in. × 32 in. = 1,536 in.²

The area of the triangle AIL, A₂ = 1/2 × Base × Height of the triangle

The base length of the triangle, L = IA = 48 in.

The height of the triangle, ht = 12 in.

∴ A₂ = L × ht

A₂ = 48 in. × 12 in. = 576 in.²

The area of the triangle AIL, A₂ = 576 in.²

The area of the figure, A = The area of the rectangle, A₁ + The area of the triangle, A₂

A = A₁ + A₂

∴ A = 1,536 in.² + 576 in.² = 2,112 in.²

The area of the figure, A = 2,112 in².

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3 years ago