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Pie
3 years ago
6

If y varies directly as x, and y = - 4 when x=32, find why when x=3

Mathematics
1 answer:
Sonbull [250]3 years ago
8 0
Attached the solution and work.

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Trying to help my bro solve this <br>Y= -2x+2
Alexus [3.1K]
Are you trying to graph it because it is in y=mx+b form.

3 0
3 years ago
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Which statement about the following equation is true?<br>2x2-9x+2-1​
Furkat [3]

Complete Question:

Which statement about the following equation is true?

2x^2-9x+2 = -1

A) The discriminant is less than 0, so there are two real roots

B) The discriminant is less than 0, so there are two complex roots

C) The discriminant is greater than 0, so there are two real roots

D) The discriminant is greater than 0, so there are two complex roots

Answer:

C) The discriminant is greater than 0, so there are two real roots

Step-by-step explanation:

The given equation is 2x^2-9x+2 = -1 which by simplification becomes

2x^2 - 9x + 3 = 0

For a quadratic equation of the form ax^2 + bx + c = 0, the discriminant is given by the equation, D = b^2 - 4ac

If the discriminant D is greater than 0, the roots are real and different

If the discriminant D is equal to 0, the roots are real and equal

If the discriminant D is less than 0, the roots are imaginary

For the quadratic equation under consideration, a = 2, b = -9, c = 3

Let us calculate the discriminant D

D = (-9)² - 4(2)(3)

D = 81 - 24

D = 57

Since the Discriminant D is greater than 0, the roots are real and different.

3 0
3 years ago
Please help will give brainlest<br><br> Question 67x3-34+49x2
tresset_1 [31]

Answer:

265

Step-by-step explanation: Used a Calculator

8 0
2 years ago
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Magdalena Figueroa's covered medical care bills for a recent illness were $8,440.00. Her major medical policy had a coinsurance
devlian [24]
Medical bill = $8,440
Deductible = $400
Coinsurance plan = Medical policy 80% of all expenses above $400

Amount to pay = 400+ (8440-400)*20/100 = 400+1608 = $2,008
8 0
3 years ago
Suppose you pick two cards from a deck of 52 playing cards. What is the probability that they are both queens?
photoshop1234 [79]

Answer:

0.45% probability that they are both queens.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes

The combinations formula is important in this problem:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Desired outcomes

You want 2 queens. Four cards are queens. I am going to call then A,B,C,D. A and B is the same outcome as B and A. That is, the order is not important, so this is why we use the combinations formula.

The number of desired outcomes is a combinations of 2 cards from a set of 4(queens). So

D = C_{4,2} = \frac{4!}{2!(4-2)!} = 6

Total outcomes

Combinations of 2 from a set of 52(number of playing cards). So

T = C_{52,2} = \frac{52!}{2!(52-2)!} = 1326

What is the probability that they are both queens?

P = \frac{D}{T} = \frac{6}{1326} = 0.0045

0.45% probability that they are both queens.

4 0
3 years ago
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