Let p be the proportion. Let c be the given confidence level , n be the sample size.
Given: p=0.3, n=1180, c=0.99
The formula to find the Margin of error is
ME = 
Where z (α/2) is critical value of z.
P(Z < z) = α/2
where α/2 = (1- 0.99) /2 = 0.005
P(Z < z) = 0.005
So in z score table look for probability exactly or close to 0.005 . There is no exact 0.005 probability value in z score table. However there two close values 0.0051 and 0.0049 . It means our required 0.005 value lies between these two probability values.
The z score corresponding to 0.0051 is -2.57 and 0.0049 is -2.58. So the required z score will be average of -2.57 and -2.58
(-2.57) + (-2.58) = -5.15
-5.15/2 = -2.575
For computing margin of error consider positive z score value which is 2.575
The margin of error will be
ME = 
=
= 2.575 * 0.0133
ME = 0.0342
The margin of error is 0.0342
Answer:
x=39
Step-by-step explanation:
Answer:
a) 0.5588
b) 0.9984
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 24
Standard Deviation, σ = 6.4
We are given that the distribution of score is a bell shaped distribution that is a normal distribution.
Formula:
a) P(score between 20 and 30)

b) Sampling distribution
Sample size, n = 22
The sample will follow a normal distribution with mean 24 and standard deviation,

c) P(mean score of sample is between 20 and 30)

You simplefie them and get 1/2 for 4/8
2/3 for 8/12
3/4 cannot be somplified
Step-by-step explanation:
x+10=116
x=116-110
=106
x=106