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zheka24 [161]
3 years ago
12

Subject On-Time Assignment Submission On-Time Arrival to Class Physics 89.7% 82.3% Math 88.2% 88.7% Chemistry 89.4% 83.1% Biolog

y 90.1% 82.4% Total 88.5% 84.7% The probabilities by subject of on-time assignment submission and on-time arrival to class are given in the table. What is the chance that the subject is physics if an assignment is submitted on time? A. 82.3% B. 88.5% C. 89.7% D. insufficient data
Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
7 0

Answer:

  D. insufficient data

Step-by-step explanation:

We need to know the number of assignments in each class before we can tell the probability of interest.

__

If we assume the same number of assignments in each class, then 25.1% of on-time assignments were in physics. We note this is not an answer choice, further confirming we have <em>insufficient data</em>.

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If George put $600 in a savings account at a simple interest rate for each year. What was his interest rate, r, if after 3 years
egoroff_w [7]

Answer:

  6%

Step-by-step explanation:

The multiplier on George's money is ...

  $708/$600 = 1.18

This value is ...

  1 + rt = 1.18 . . . . . for t = 3

  3r = 0.18 . . . . . . subtract 1; next divide by 3

  r = 0.06 = 6%

The simple interest rate on George's account is 6%.

8 0
3 years ago
Which of the following are square roots of —8 + 8i/3? Check all that apply.
8090 [49]

Answer:

Options (2) and (3)

Step-by-step explanation:

Let, \sqrt{-8+8i\sqrt{3}}=(a+bi)

(\sqrt{-8+8i\sqrt{3}})^2=(a+bi)^2

-8 + 8i√3 = a² + b²i² + 2abi

-8 + 8i√3 = a² - b² + 2abi

By comparing both the sides of the equation,

a² - b² = -8 -------(1)

2ab = 8√3

ab = 4√3 ----------(2)

a = \frac{4\sqrt{3}}{b}

By substituting the value of a in equation (1),

(\frac{4\sqrt{3}}{b})^2-b^2=-8

\frac{48}{b^2}-b^2=-8

48 - b⁴ = -8b²

b⁴ - 8b² - 48 = 0

b⁴ - 12b² + 4b² - 48 = 0

b²(b² - 12) + 4(b² - 12) = 0

(b² + 4)(b² - 12) = 0

b² + 4 = 0 ⇒ b = ±√-4

                     b = ± 2i

b² - 12 = 0 ⇒ b = ±2√3

Since, a = \frac{4\sqrt{3}}{b}

For b = ±2i,

a = \frac{4\sqrt{3}}{\pm2i}

  = \pm\frac{2i\sqrt{3}}{(-1)}

  = \mp 2i\sqrt{3}

But a is real therefore, a ≠ ±2i√3.

For b = ±2√3

a = \frac{4\sqrt{3}}{\pm 2\sqrt{3}}

a = ±2

Therefore, (a + bi) = (2 + 2i√3) and (-2 - 2i√3)

Options (2) and (3) are the correct options.

6 0
3 years ago
What is 3,4,5 plz and thank you
Tcecarenko [31]
For 3 it’s b. For 2 it’s 8. For 4 it’s the whole number
8 0
3 years ago
Nancy shot a 24 on 4 holes of golf. At this rate, what can she expect her score to be if she plays all 18 holes?
Elden [556K]

Answer:

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Step-by-step explanation:

"At this rate, ..." means we're to assume Nancy's score is proportional to the number of holes:

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Multiplying by 18, we get ...

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Nancy can expect a score of 108 on 18 holes.

4 0
3 years ago
Solve for j.<br> J + 22/8 =8
Monica [59]

Answer:

j=5.25

Step-by-step explanation:

j+22/8=8

j=8/1-22/8

j=64-22/8

j=5.25

Proof:

5.25+22/8=8

525/100+22/8=8

4200+2200/800=8

6400/800=8

8=8

7 0
3 years ago
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