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elixir [45]
3 years ago
12

Which diagram shows ∠1 and ∠2 as vertical angles?

Mathematics
1 answer:
Mariulka [41]3 years ago
6 0
When two line cross each othe vertical angles are formed
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PLEASE HELP ITS MY TRIMESTER TEST MY MOM WILL KILL ME IF I FAIL! <3 WILL MARK BRAINLIST!
Artyom0805 [142]

Answer:

r =2.9985yd

Step-by-step explanation:

Given that the circumference of a circle is 2\pir

where r is the radius and \pi = 3.1415926....

You have

2\pir = 18.84 yd

2(3.1415926)r = 18.84 yd

6.2831r = 18.84yd

divide through by 6.2831

r = 2.9985yd = aprox 3yds

7 0
3 years ago
This year, a gram planted 400,000 corn stalks.last year, the farm planted 275,650 corn stalks how many more corn stalks did the
In-s [12.5K]
400000-275650=124350
3 0
3 years ago
FIND THE EQUATION OF THE LINE!!!<br>USE EXACT NUMBERS<br><br>EXAMPLE!<br><br>y= ( )x + ( ) ​
Korvikt [17]

Answer:

y=mx+b is the form to write this equation. M is the slope and B is the y intercept. therefore:

y=4x-9

Step-by-step explanation:

3 0
3 years ago
Which term contains a coefficient?<br> m + 3n + p + 3
natulia [17]
The answer is 3n because the 3 is the coefficient
7 0
3 years ago
Read 2 more answers
What is the following product? <br>(4x square root 5x^2 + 2^2 square root 6)^2​
tangare [24]

The product is 104 x^{4}+16 \sqrt{30} x^{4}

Explanation:

The given expression is \left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}

We need to determine the product of the given expression.

First, we shall simplify the given expression.

Thus, we have,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x \sqrt{5} x+2 x^{2} \sqrt{6}\right)^2

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)^2

Expanding the expression, we have,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)

Now, we shall apply FOIL, we get,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}

Simplifying the terms, we have,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=16 \cdot 5 x^{4}+16 \sqrt{30} x^{4}+4 \cdot 6 x^{4}

Multiplying, we get,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=80 x^{4}+16 \sqrt{30} x^{4}+24 x^{4}

Adding the like terms, we get,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=104 x^{4}+16 \sqrt{30} x^{4}

Thus, the product of the given expression is 104 x^{4}+16 \sqrt{30} x^{4}

7 0
3 years ago
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