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3 years ago

Which diagram shows ∠1 and ∠2 as vertical angles?

Mathematics

1 answer:

Mariulka [41]3 years ago

6 0

When two line cross each othe vertical angles are formed

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PLEASE HELP ITS MY TRIMESTER TEST MY MOM WILL KILL ME IF I FAIL! <3 WILL MARK BRAINLIST!

Artyom0805 [142]

Answer:

r =2.9985yd

Step-by-step explanation:

Given that the circumference of a circle is 2 $\pi$ r

where r is the radius and $\pi$ = 3.1415926....

You have

2 $\pi$ r = 18.84 yd

2(3.1415926)r = 18.84 yd

6.2831r = 18.84yd

divide through by 6.2831

r = 2.9985yd = aprox 3yds

7 0

3 years ago

This year, a gram planted 400,000 corn stalks.last year, the farm planted 275,650 corn stalks how many more corn stalks did the

In-s [12.5K]

400000-275650=124350

3 0

3 years ago

FIND THE EQUATION OF THE LINE!!! USE EXACT NUMBERS EXAMPLE! y= ( )x + ( )

Korvikt [17]

Answer:

y=mx+b is the form to write this equation. M is the slope and B is the y intercept. therefore:

y=4x-9

Step-by-step explanation:

3 0

3 years ago

Which term contains a coefficient? m + 3n + p + 3

natulia [17]

The answer is 3n because the 3 is the coefficient

7 0

3 years ago

Read 2 more answers

What is the following product? (4x square root 5x^2 + 2^2 square root 6)^2

tangare [24]

The product is $104 x^{4}+16 \sqrt{30} x^{4}$

Explanation:

The given expression is $\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}$

We need to determine the product of the given expression.

First, we shall simplify the given expression.

Thus, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x \sqrt{5} x+2 x^{2} \sqrt{6}\right)^2$

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)^2$

Expanding the expression, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)$

Now, we shall apply FOIL, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}$

Simplifying the terms, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=16 \cdot 5 x^{4}+16 \sqrt{30} x^{4}+4 \cdot 6 x^{4}$

Multiplying, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=80 x^{4}+16 \sqrt{30} x^{4}+24 x^{4}$

Adding the like terms, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=104 x^{4}+16 \sqrt{30} x^{4}$

Thus, the product of the given expression is $104 x^{4}+16 \sqrt{30} x^{4}$

7 0

3 years ago