Kai had a gross weekly paycheck of $616 last week. Kai worked 6 hours for 4 of the days and 8 hours on 1 day. What is Kai's hour
2 answers:
Answer:
Kai's hourly rate of pay is $19.25.
Step-by-step explanation:
Kay's hourly rate of pay is his gross weekly paycheck divided by the total number of hours he worked.
The problem states that:
Kai worked 6 hours for 4 of the days and 8 hours on 1 day. This means that he worked 4*6 + 8 = 32 hours on the week.
He earned $616.
So his hourly rate of pay is:
Kai's hourly rate of pay is $19.25.
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Answer:
a) 0.7412 = 74.12% probability that all the three orders will be filled correctly.
b) 0.0009 = 0.09% probability that none of the three will be filled correctly
c) 0.0245 = 2.45% probability that at least one of the three will be filled correctly.
d) 0.9991 = 99.91% probability that at least one of the three will be filled correctly
e) 0.0082 = 0.82% probability that only your order will be filled correctly
Step-by-step explanation:
For each order, there are only two possible outcomes. Either it is filled correctly, or it is not. Orders are independent. This means that we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
The percentage of orders filled correctly at Burger King was approximately 90.5%.
This means that
You and 2 friends:
So 3 people in total, which means that
a. What is the probability that all the three orders will be filled correctly?
This is P(X = 3).
0.7412 = 74.12% probability that all the three orders will be filled correctly.
b. What is the probability that none of the three will be filled correctly?
This is P(X = 0).
0.0009 = 0.09% probability that none of the three will be filled correctly.
c. What is the probability that one of the three will be filled correctly?
This is P(X = 1).
0.0245 = 2.45% probability that at least one of the three will be filled correctly.
d. What is the probability that at least one of the three will be filled correctly?
This is
With what we found in b:
0.9991 = 99.91% probability that at least one of the three will be filled correctly.
e. What is the probability that only your order will be filled correctly?
Yours correctly with 90.5% probability, the other 2 wrong, each with 9.5% probability. So
0.0082 = 0.82% probability that only your order will be filled correctly