Answer :
6. x=28
7.x =6
8. x =9
9. x =9
Step-by-step explanation:
6.
(x+2)/10 = 3
Cross multiply
x+2 = 10 ×3
x+2 =30
Collect like terms and simplify
x =30-2
x = 28
7.
8x +9 -5x= 27
Collect like terms and simplify
8x-5x =27-9
3x =18
Divide both sides of the equation by 3
3x/3 = 18/3
x = 6
8.
10x+8=8x+26
Collect like terms
10x-8x=26-8
2x = 18
Divide both sides of the equation by 2
2x/2 = 18/2
x = 9
9.
2(x-5)+4x=x+35
Use 2 to open the bracket
2 × x =2x
2×(-5) =-10
2x-10+4x =x+35
Collect like terms and simplify
2x+4x-x = 35+10
5x = 45
Divide both sides of the equation by 5
5x/5 = 45/5
x =9
Answer:
Tonga trench Elevation = 35,702ft
South sandwich trench elevation = 23,737ft
Step-by-step explanation:
Given the following:
Tonga trench Elevation = 35,702 Feets
South sandwich trench elevation = 23,737 Feets
Expressing both numbers as rational numbers :
Both the Tonga trench Elevation and South sandwich trench elevation are already stated as rational numbers because all integers are rational numbers, be it expressed as a quotient or proportion of integer numbers ( that is numbers that are expressed without decimal components.
Therefore, rational expression for both are :
Tonga trench Elevation = 35,702ft
South sandwich trench elevation = 23,737ft
Answer:
P= 20x+2 ft
Step-by-step explanation:
________
I I
I I 3x + 7ft
________
7x - 6ft
P= (7x - 6 + 7x - 6) + (3x + 7 + 3x + 7)
= (14x - 12) + (6x + 14)
= 20x + 2 ft
The plane will end up flying 5.02°.
The plan's speed relative to the ground will be 645.91 km/hr.
Solution:
Use the cosine formula,
Substitute the given values in the formula,
Taking square root on both sides, we get
R = 645.91 km/hr
This is the grouped speed of the aircraft.
To find θ use sine rule.
Do cross multiplication, we get
sin θ = 0.0875
θ = 5.02°
This is known as the drift angle and is the correction the pilot should apply to remain on course.
The heading is the direction the aircraft's nose is pointing which is
The track is the actual direction over the ground which is θ = 5.02°
An alternative method to this would be to separate each vector into vertical and horizontal components and add.
The resultant can be found using Pythagoras.
