Kai had a gross weekly paycheck of $616 last week. Kai worked 6 hours for 4 of the days and 8 hours on 1 day. What is Kai's hour
2 answers:
Answer:
Kai's hourly rate of pay is $19.25.
Step-by-step explanation:
Kay's hourly rate of pay is his gross weekly paycheck divided by the total number of hours he worked.
The problem states that:
Kai worked 6 hours for 4 of the days and 8 hours on 1 day. This means that he worked 4*6 + 8 = 32 hours on the week.
He earned $616.
So his hourly rate of pay is:
Kai's hourly rate of pay is $19.25.
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Answer: d) 3 hours.
Step-by-step explanation:
Let x be the required number of hours for which the total fee charged by the companies the same.
Given: Peppy Pets charges a flat fee of $15 plus $3 per hour .
So Total charge = 15+3x ( in dollars)
Happy Hounds charges a flat fee of $21 plus $1 per hour.
So Total charge = 21+x ( in dollars)
When the total charge for both companies are the same, then
Hence, the correct option is d) 3 hours.
Answer:
a. P(C) = 0.03
P(test+ | C) = 0.89
P(test- | no C) = 0.93
b. Tree diagram is attached.
c. P(test+) = 0.0946
d. P(C | test+) = 0.2822
Step-by-step explanation:
a. Let C denote Lung Cancer The probability that a heavy smoker will develop lung cancer is 3% i.e. 0.03.
If lung cancer is present, the CT scan result comes out to be positive 89% of the times while if lung cancer is not present, the results are negative 93% of the time. Let test+ denote that the test result is positive and test- denote that the test result is negative.
P(C) = 0.03
P(test+ | C) = 0.89
P(test- | no C) = 0.93
b. The first pair of branches represent whether the individual has cancer or not.
P(C) = 0.03
P(no C) = 1 - 0.03 = 0.97
The second pair of branches will represent if the test result came out positive or negative.
For patients with cancer, P(test+) = 0.89, P(test-) = 1 - 0.89 = 0.11
For patients with no cancer, P(test -) = 0.93, P(test+)= 1 - 0.93 = 0.07.
The tree diagram is attached as an image file.
c. P(test+) = P(C)*P(test+| C) + P(No C)*P(test+| No C)
= (0.03)(0.89) + (0.97)(0.07)
= 0.0267 + 0.0679
P(test+) = 0.0946
d. P(C | test+) = P(C ∩ test+) / P(test+)
= P(C)*P(test+ | C) / P(test+)
= (0.03)*(0.89) / 0.0946
P(C | test+) = 0.2822
