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3 years ago

Please help me 20 points

Mathematics

2 answers:

Jobisdone [24]3 years ago

4 0

Answer is c. i think

svetlana [45]3 years ago

3 0

Answer is C............

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Alguien me ayuda a resolver esto por favor es urgente 1/2+1/4=

natulia [17]

Answer:

Step-by-step explanation:

Solo quiero ganar puntos

5 0

3 years ago

Suppose that each time Giannis Antetokounmpo shoots a free throw, he has a 3/4 probability of success. If Giannis shoots three f

GREYUIT [131]

Answer:

84.38% probability that he succeeds on at least two of them

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either Giannis makes it, or he does not. The free throws are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

He has a 3/4 probability of success.

This means that $p = \frac{3}{4} = 0.75$

Giannis shoots three free throws

This means that $n = 3$

What is the probability that he succeeds on at least two of them

$P(X \geq 2) = P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{3,2}.(0.75)^{2}.(0.25)^{1} = 0.4219$

$P(X = 3) = C_{3,3}.(0.75)^{3}.(0.25)^{0} = 0.4219$

$P(X \geq 2) = P(X = 2) + P(X = 3) = 0.4219 + 0.4219 = 0.8438$

84.38% probability that he succeeds on at least two of them

6 0

3 years ago

A manufacturing company measures the weight of boxes before shipping them to the customers. If the box weights have a population

NikAS [45]

Answer:

<u>The probability that the average weight of the boxes will exceed 94 pounds is 43.25%</u>

Step-by-step explanation:

1. Let's review the information provided to answer the question correctly:

Mean of the population of box weights = 90 pounds

Standard deviation of the population of box weights = 24 pounds

Sample size = 36 boxes

2. What is the probability that the average weight of the boxes will exceed 94 lb?

For answering this question, we will use the z-scores table.

For using the correct z-score, we should use the correct standard deviation. In this case, we have that:

94 - 90 = 4 pounds above the mean.

4 pounds are 4/24 of the standard deviation,

therefore, simplifying:

4/24 = 1/6 = 0.1666......and we'll round to 0.17

z-score is 0.17 because 4 pounds is 1/6 of the standard deviation (24).

The probability of a z-score is 0.5675, but in this case we're asked by a weight over 94 pounds, not under 94 pounds, thus:

1 - 0.5675 = 0.4325

<u>The probability that the average weight of the boxes will exceed 94 pounds is 43.25%</u>

8 0

3 years ago

Is the statement 2(3+5x)=6+5x always true?

mihalych1998 [28]

No that statement is not always true. There is only one solution to this equation.

5 0

3 years ago

Read 2 more answers

Question 26 teresa runs 3 miles in 28 minutes. at the same rate, how many miles would she run in 42 minutes?

Leya [2.2K]

The answer is 4.5 miles. Hope it helps!

8 0

3 years ago