Im not sure but I think it is like 65
Answer:
x = ln(4/3)
Step-by-step explanation:
6e^x-4e^-x=5
We can subtract 5 from each side
6e^x-4e^-x -5 =5-5
6e^x-4e^-x-5=0
Multiply by e^x
e^x(6e^x-4e^-x-5)=0*e^x
Distribute
6e^2x - 4 e^0 -5e^x =0
Let m = e^x
6m^2 - 4 -5m =0
Rearrange
6m^2 -5m-4 =0
Factor
(2m+1) (3m-4)=0
Using the zero product property
2m+1 = 0 and 3m-4 =0
2m=-1 3m=4
m = -1/2 m = 4/3
Replace m with e^x
e^x = -1/2 and e^x = 4/3
But e^x cannot be negative so the first is not a solution
e^x = 4/3
Take the ln of both side
ln (e^x) = ln (4/3)
x = ln(4/3)
We know a square is four equal sides. Saying this there are seven squares between A and C so, with the knowns of four equal sides and seven square between A and C you can divide 42/7=6. With this information count six squares to the right from A and the same for C with a result of
B(2,4), and D(2,-3) per graph.
A and b are irrational because we can’t graph them on a number line. One is a square root and the either is a decimal which is combined with the square root. The second is rational because the square root of 225 is 15 which can be graphed on a number line. 2.5 can also be graphed on a number line. We multiply these and get 37.5 which is possible to graph. 20 is irrational since it is not a perfect square. Therefore, it is difficult to add a square root and a decimal.
Huy b yan alam ko na yan matagal na ako nyan