Answer:
Following are the code to the given question:
#include <iostream>//header file
using namespace std;
class Window //defining a class Window
{
private:
int width, height;//defining integer variable
public:
friend ostream& operator << (ostream& stm, Window& width)//defining a friend function that takes two parameters
{
return stm<<"a ("<<width.width<<" x "<<width.height<<") window"; //use return keyword that return its values
}
Window(int width, int height): width(width), height(height)//defining parameterized constructor that inherit width and height in its parameters
{}
};
int main() //Main method
{
Window w(80,90);//calling class constructor
cout<<w;//print object value
return 0;
}
Output:
a (80 x 90) window
Explanation:
In the above code, a class "Window" is defined that uses a friend function "ostream& operator" is declared that uses the "ostrea&" as a data type to hold two-variable "stm and w" in its parameter, and declared the parameterized constructor to hold value by inheriting width and height in its parameters.
Inside the main method, a class object is created that calls the constructor and uses the print method to print object value.
Closeness to the true value of a measurement is accuracy
Answer:
Answer is in the provided screenshot!
Explanation:
Steps required to solve this problem:
1 - define what characters are "vowels" by assigning them to an array.
2 - create a variable to record the amount of vowels there are in the string.
3 - convert the input string into a character array and iterate through each character
4 - for each of the character of the string we go through, check if it matches any of the vowels
5 - return true if the vowel count is greater than 1
Alternative methods using the Java Stream API have also been wrote, please respond if you require them.
Answer:
Vehicle forensics is a process that yields a myriad of data potentially helpful to all kinds of investigations, from law enforcement cases, to insurance fraud, to accident reconstruction. Many newer vehicles (generally 2008 and newer) are equipped with an infotainment system.
In computer science, a 2–3 tree is a tree data structure, where every node with children (internal node) has either two children (2-node) and one data element or three children (3-nodes) and two data elements. According to Knuth, "a B-tree of order 3 is a 2-3 tree."
