Answer:
public class array{
public static void main(String []args){
int[] array = {2,4,7,1,9};
int num_vals = array.length;
for(int i=0;i<num_vals;i++){
System.out.println(array[i] + " ");
}
for(int i=num_vals-1;i>=0;i--){
System.out.println(array[i] + " ");
}
}
}
Explanation:
First create the class in the java programming.
Then create the main function and declare the array with values.
Store the size of array in num_vals variable by using the function array.length.
create a for loop to iterate the each element in the array and then print on the screen with spaces and newline.
it traverse the loop from first to last.
Then, again create the for loop to iterate the each element in the array and then print on the screen with spaces and newline but the traversing start from last to first.
Answer:
Eraser tool -removes the unwanted part of the drawing.
Row -horizontal space running from left to right.
Text -Primary component of a multimedia.
Drawing Area -Working are of ms point program.
I hope this helps!! Correct me plz if I'm wrong. If I'm right, could you mark me as brainliest?
Answer:
See the code below and the algorithm explanation on the figure.
Explanation:
The explanation in order to get the answer is given on the figure below.
Solving this problem with C. The program is given below:
#include <stdio.h>
int main(void) {
int n, Even=0, Odd=0, Zeros=0;
for (;;) {
printf("\nEnter the value the value that you want to check(remember just integers): ");
//IF we input a non-numeric character the code end;
if (scanf("%d", &n) != 1) break;
if (n == 0) {
Zeros++;
}
else {
if (n % 2) {
Even++;
}
else {
Odd++;
}
}
}
printf("for this case we have %d even, %d odd, and %d zero values.", Even, Odd, Zeros);
return 0;
}
