Two integers, a and b, have a product of 24. What is the least possible sum of a and b?

1 answer:

7 0

The least possible sum is 10.

The pairs of factors for 24 are (1,24), (2,12), (3,8), (4,6) with sums 25, 14, 11, 10. So the numbers are 4 and 6.

6+4

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How to solve 4/7y-2 = 3/7 + 3/14

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Solution

1) Simplify $\frac{4}{7y}$ to $\frac{4y}{7}$
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2) Simplify $\frac{3}{7}$ + $\frac{3}{14}$ to 914
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3) Add 2 to both sides
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4) Simplify $\frac{9}{14
}$ +2 to $\frac{37}{14}$
$\frac{4y}{7}$ = $\frac{37}{14}$

5) Multiply both sides by 7
4y= $\frac{37}{14}$ ×7

6) Simplify $\frac{37}{14}$ ×7 to $\frac{259}{14}$
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7) Simplify $\frac{259}{14}$ to $\frac{37}{2}$
$\frac{4y}{7}$ = $\frac{37}{2}$

8) Divide both sides by 4
y= $\frac{37}{2}$ ×4

9) Simplify 2×4 to 8
y= $\frac{37}{8}$

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