Answer:
let's find the gradient first. (m)
Step-by-step explanation:
(10,3) (6,31)
y²-y¹/x²-x¹
31-3/6-3
28/3
(m) =28/3
y-y¹=m(x-x¹)
let's take y¹=3, x¹=10 and m= 28/3
y-3=28/3(x -10)
y-3=(28/3)x -128/3
taking LCM=3
3y-9=28x-128
3y=28x -128+9
3y=28x-119
Soo your equation is:
3y=28x-119
a = -1 and b = 5
5a-7b+b2
5(-1) - 7(5) + 5^2
-5 - 35 + 25
-40 + 25
-15
-15 would be the result
Best Regards, Mike
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Answer:
x = -1 and y = -1
Step-by-step explanation:
to solve this equation we say
let
2x-5y=3.......................................... equation 1
4y-x=-3............................................equation 2
from equation 2
4y-x=-3............................................equation 2
4y + 3 = x
i.e
x = 4y + 3 ............................................. equation 3
put x = 4y + 3 in equation 1
2(4y +3) - 5y = 3
8y + 6 -5y = 3
3y +6 = 3
3y= 3-6
3y -3
divide both sides by the coefficient of y which is 3
3y/3 = -3/3
y = -1
put y = -1 into equation 3
x = 4y + 3 ............................................. equation 3
x = 4(-1) + 3
x = -4 + 3
x = -1
therefore the value of x = -1 and y = -1 respectively
Take a look at the horiz. line. It has arrows at both ends. That means that x goes on forever in both directions. Thus, the domain of this function is (-inf, +inf).
