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atroni [7]
3 years ago
9

Prove that if AC=DF and AB=DE then BC=EF

Mathematics
1 answer:
Step2247 [10]3 years ago
8 0
In triangle ABC and DEF
AC =DF, [ given ]
AB =DE, [ given ]
angle A = angle D
by SAS
ABC congruent to triangle DFE
so
BC = EF, [ CPCTC]
hence proved
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What is the y-value of the solution to the system of equations?
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Answer:

{x = -3 , y=2  (Isolved for both variables be elimination)

Step-by-step explanation:

Solve the following system:

{3 x + 5 y = 1 | (equation 1)

7 x + 4 y = -13 | (equation 2)

Swap equation 1 with equation 2:

{7 x + 4 y = -13 | (equation 1)

3 x + 5 y = 1 | (equation 2)

Subtract 3/7 × (equation 1) from equation 2:

{7 x + 4 y = -13 | (equation 1)

0 x+(23 y)/7 = 46/7 | (equation 2)

Multiply equation 2 by 7/23:

{7 x + 4 y = -13 | (equation 1)

0 x+y = 2 | (equation 2)

Subtract 4 × (equation 2) from equation 1:

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0 x+y = 2 | (equation 2)

Divide equation 1 by 7:

{x+0 y = -3 | (equation 1)

0 x+y = 2 | (equation 2)

Collect results:

Answer:  {x = -3 , y=2

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