(-2,0) option b is the correct answer
The average of the five consecutive numbers ending with b in discuss when expressed in terms of a is; Choice D; a+3.
<h3>What is the average of five consecutive integers ending with b?</h3>
First, since it was given in the task content that the average of six positive consecutive odd integers starting with a is equal to b, it therefore follows that;
(a+a+2+a+4+a+6+a+8+a+10)/6 = b
6b=6a+30
b=a+5
Also, let the average of the consecutive intergers ending with b be denoted by; x.
(b+b-1+b-2+b-3+b-4)/5 = x
=(5b-10)/5
=b–2
The average, x=b – 2 (where b = a-5)
Ultimately, the value of the required average is; = a+5-2 = a+3.
Read more on average of integers;
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Eisismokistee form is their je. Ejeieiek wowow
3x + 2y = 12
subtract 3x from both sides
2y = -3x + 12
divide all terms by 2 so that you can have only the y on the left side
y = -3/2x + 6
And that is your answer!
Hope this helped!! :)
Answer:
6 units away from 0.
Step-by-step explanation:
when move to 6 you count the units.
