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DanielleElmas [232]
3 years ago
7

What are the sine cosine and tangent of theta=7pi/4 radians

Mathematics
2 answers:
Andrei [34K]3 years ago
8 0

Answer:

\sin\theta=-\frac{1}{\sqrt{2}}

\cos\theta=\frac{1}{\sqrt{2}}

\tan\theta=-1.

Step-by-step explanation:

We have to find the value of sine cosine and tangent of \theta=\frac{7\pi}{4} radians.

\frac{7\pi}{4}\times \frac{180}{\pi}=315^{\circ}

So, \theta=\frac{7\pi}{4} lies in 4th quadrant. Sine and tangent are negative in 4th quadrant.

The value of sinθ is

\sin\theta=\sin (\frac{7\pi}{4})

\sin\theta=\sin (2\pi-\frac{\pi}{4})

\sin\theta=-\sin (\frac{\pi}{4})

\sin\theta=-\frac{1}{\sqrt{2}}

The value of cosθ is

\cos\theta=\cos (\frac{7\pi}{4})

\cos\theta=\cos (2\pi-\frac{\pi}{4})

\cos\theta=\cos (\frac{\pi}{4})

\cos\theta=\frac{1}{\sqrt{2}}

The value of tanθ is

\tan\theta=\tan (\frac{7\pi}{4})

\tan\theta=\tan (2\pi-\frac{\pi}{4})

\tan\theta=-\tan (\frac{\pi}{4})

\tan\theta=-1

Therefore \sin\theta=-\frac{1}{\sqrt{2}}, \cos\theta=\frac{1}{\sqrt{2}} and \tan\theta=-1.

FrozenT [24]3 years ago
6 0

Answer:

see explanation

Step-by-step explanation:

\frac{7\pi }{4} is in the fourth quadrant

Where sin and tan are < 0 , cos > 0

The related acute angle is 2π - \frac{7\pi }{4} = \frac{\pi }{4}

Hence

sin([\frac{7\pi }{4} ) = - sin(\frac{\pi }{4}) = - \frac{1}{\sqrt{2} } = - \frac{\sqrt{2} }{2}

cos(\frac{7\pi }{4}) = cos(\frac{\pi }{4}) =  \frac{\sqrt{2} }{2}

tan(\frac{7\pi }{4}= - tan(\frac{\pi }{4} = - 1

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