I been trying to figure the question out for the past 20 minutes and I can’t find the answer please help. (Question in picture)

Mathematics

1 answer:

lesantik [10]3 years ago

8 0

Answer:

125°°

Step-by-step explanation:

∠DFC is a vertical angle with ∠BFE. As such, it is the sum of the right angle and the one marked 35°.

∠DFC = 90° +35°

∠DFC = 125°

_____

<em>Alternate solution</em>

∠CFA = 90° = ∠CFB +∠BFA

∠CFB = 90° -35° = 55°

∠BFC and ∠CFD are a linear pair, so total 180°

∠CFD = 180 -55° = 125° = ∠DFC

You might be interested in

B) Simplify 9y - 6y + y

julsineya [31]

Answer:

The answer is 4y

Step-by-step explanation:

Simplify the expression.

Hoped this helped!

Could I perhaps get brainly?

8 0

3 years ago

Read 2 more answers

An automated egg carton loader has a 1% probability of cracking an egg, and a customer will complain if more than one egg per do

vaieri [72.5K]

Answer:

a) Binomial distribution B(n=12,p=0.01)

b) P=0.007

c) P=0.999924

d) P=0.366

Step-by-step explanation:

a) The distribution of cracked eggs per dozen should be a binomial distribution B(12,0.01), as it can model 12 independent events.

b) To calculate the probability of having a carton of dozen eggs with more than one cracked egg, we will first calculate the probabilities of having zero or one cracked egg.

$P(k=0)=\binom{12}{0}p^0(1-p)^{12}=1*1*0.99^{12}=1*0.886=0.886\\\\P(k=1)=\binom{12}{1}p^1(1-p)^{11}=12*0.01*0.99^{11}=12*0.01*0.895=0.107$

Then,

$P(k>1)=1-(P(k=0)+P(k=1))=1-(0.886+0.107)=1-0.993=0.007$

c) In this case, the distribution is B(1200,0.01)

$P(k=0)=\binom{1200}{0}p^0(1-p)^{12}=1*1*0.99^{1200}=1* 0.000006 = 0.000006 \\\\ P(k=1)=\binom{1200}{1}p^1(1-p)^{1199}=1200*0.01*0.99^{1199}=1200*0.01* 0.000006 \\\\P(k=1)= 0.00007\\\\\\P(k\leq1)=0.000006+0.000070=0.000076\\\\\\P(k>1)=1-P(k\leq 1)=1-0.000076=0.999924$