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8_murik_8 [283]
3 years ago
15

I been trying to figure the question out for the past 20 minutes and I can’t find the answer please help. (Question in picture)

Mathematics
1 answer:
lesantik [10]3 years ago
8 0

Answer:

  125°°

Step-by-step explanation:

∠DFC is a vertical angle with ∠BFE. As such, it is the sum of the right angle and the one marked 35°.

  ∠DFC = 90° +35°

  ∠DFC = 125°

_____

<em>Alternate solution</em>

∠CFA = 90° = ∠CFB +∠BFA

∠CFB = 90° -35° = 55°

∠BFC and ∠CFD are a linear pair, so total 180°

∠CFD = 180 -55° = 125° = ∠DFC

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Answer:

BD = <u>1</u> unit

AD = <u>1</u> unit

AB = <u>1.6</u> units

AC = <u>1.6</u> units

Step-by-step explanation:

In the picture attached, the triangle ABC is shown.

Given that triangle ABC is isosceles, then ∠B = ∠C

∠A + ∠B + ∠C = 180°

36° + 2∠B = 180°

∠B = (180° - 36°)/2

∠B = ∠C  = 72°

From Law of Sines:

sin(∠A)/BC = sin(∠B)/AC = sin(∠C)/AB

(Remember that BC is 1 unit long)

AB = AC = sin(72°)/sin(36°) = 1.6

In triangle ABD, ∠B = 72°/2 = 36°, then:

∠A + ∠B + ∠D = 180°

36° + 36° + ∠D = 180°

∠D =  180° - 36° - 36° = 108°

From Law of Sines:

sin(∠A)/BD = sin(∠B)/AD = sin(∠D)/AB

(now ∠A = ∠B)

BD = AD = sin(∠A)*AB/sin(∠D)

BD = AD = sin(36°)*1.6/sin(108°) = 1

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