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3 years ago

Divide. Write your answer in lowest terms. 3/4 divided by 6/1

1 answer:

8 0

Since dividing fractions are not possible, you must first find the reciprocal of 6/1 which is 1/6. And the equation would be written as 3/4*1/6. Cross cancel the 3 and 6 leaving 1/4*1/2=1/8. Thus, your answer is lowest terms is, 1/8.

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Function or no? <br><br> i just need a simple yes or no. ;-;

ryzh [129]

Answer:

yes

Step-by-step explanation:

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3 years ago

What is 1379 x 38 estimated

Sauron [17]

1379= 1380
38=40
1380 x 40 = 55,200
Or you can use the ≈ sign which means about so

1380 x 40 ≈ 55200

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3 years ago

Trapezoid L'M'N'P' was constructed using trapezoid LMNP. On a coordinate plane, 2 trapezoids are shown. Line segments connect ea

gregori [183]

Answer: A,B,C,E

Step-by-step explanation:

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4 years ago

Read 2 more answers

Analyze the end behavior of each function below. Then, choose one of the functions, and explain how you determined

kumpel [21]

Answer:

End behavior of a polynomial function depended on the degree and its leading coefficient.

1. If degree is even and leading coefficient is positive then

$p(x)\rightarrow \infty\text{ as }x\rightarrow \infty$

$p(x)\rightarrow \infty\text{ as }x\rightarrow -\infty$

2. If degree is even and leading coefficient is negative then

$p(x)\rightarrow -\infty\text{ as }x\rightarrow \infty$

$p(x)\rightarrow -\infty\text{ as }x\rightarrow -\infty$

3. If degree is odd and leading coefficient is positive then

$p(x)\rightarrow \infty\text{ as }x\rightarrow \infty$

$p(x)\rightarrow -\infty\text{ as }x\rightarrow -\infty$

4. If degree is odd and leading coefficient is negative then

$p(x)\rightarrow -\infty\text{ as }x\rightarrow \infty$

$p(x)\rightarrow \infty\text{ as }x\rightarrow -\infty$

(a)

$f(x)=x^4$

Here, degree is even and leading coefficient is positive.

$f(x)\rightarrow \infty\text{ as }x\rightarrow \infty$

$f(x)\rightarrow \infty\text{ as }x\rightarrow -\infty$

(b)

$g(x)=-x^4$

Here, degree is even and leading coefficient is negative.

$g(x)\rightarrow -\infty\text{ as }x\rightarrow \infty$

$g(x)\rightarrow -\infty\text{ as }x\rightarrow -\infty$

(c)

$h(x)=x^3$

Here, degree is odd and leading coefficient is positive.

$h(x)\rightarrow \infty\text{ as }x\rightarrow \infty$

$h(x)\rightarrow -\infty\text{ as }x\rightarrow -\infty$

(d)

$k(x)=-x^3$

Here, degree is odd and leading coefficient is negative.

$k(x)\rightarrow -\infty\text{ as }x\rightarrow \infty$

$k(x)\rightarrow \infty\text{ as }x\rightarrow -\infty$

4 0

3 years ago

8 - 1/3 x = 16 please help

Len [333]

Hope you can understand the handwriting :)

7 0

3 years ago