Find an equation of the line passing through the point (5,4) and parallel to the line whose equation is 2x+y=3
1 answer:
Answer:
Step-by-step explanation:
Use the point-slope formula.
y - y_1 = m(x - x_1) you have : x_1 =5 and y_1 =4
m the slope m= -2 (same slope for the line : 2x+y=3 because this lines are parallel and you can write y=-2x+3
an equation for this line is : y-4 = -2(x-5)
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For that last part you can leave your answer as a fraction of -59/20 or you can divide 29 by -59 and you’ll get -2.95.
Given:
y varies directly with x
y = 8 when x = -6
what is the value of y when x = -2?
y = kx
we need to get the constant of variation.
8 = k(-6)
8/-6 = k
4/-3 = k or - 1 1/3
y = -4/3 (-2)
y = (-4*-2) / 3
y = 8 / 3
y = 2 2/3 OR 2.67
The correct answer is Choice B. y = -1.33x ; 2.67
Answer:
4 because the edges are like vertices.
Answer:
2
Step-by-step explanation:
