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2 years ago

Find an equation of the line passing through the point (5,4) and parallel to the line whose equation is 2x+y=3

Mathematics

1 answer:

Fynjy0 [20]2 years ago

6 0

Answer:

Step-by-step explanation:

Use the point-slope formula.

y - y_1 = m(x - x_1) you have : x_1 =5 and y_1 =4

m the slope m= -2 (same slope for the line : 2x+y=3 because this lines are parallel and you can write y=-2x+3

an equation for this line is : y-4 = -2(x-5)

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ANSWER

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The standard equation of the hyperbola is

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We multiply through by 36 to obtain:

$9 {(y - 2)}^{2} - 4( {x - 2)}^{2} = 36$

We now expand to get,

$9( {y}^{2} - 4y + 4) - 4( {x}^{2} - 4x + 4) = 36$

Expand :

$9 {y}^{2} - 36y + 36 - 4 {x}^{2} + 16x - 16 = 36$

To get the general form, we equate everything to zero to get,

$9 {y}^{2} - 4 {x}^{2}- 36y + 16x - 16 = 0$

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3 years ago

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Answer:

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Step-by-step explanation:

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