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olga55 [171]
3 years ago
7

Simplified expression -6x+2/3(9-15x)-2

Mathematics
1 answer:
Artist 52 [7]3 years ago
7 0

Answer:

-16x+4

Step-by-step explanation:

-6x+2/3(9-15x)-2

Distribute

-6x +2/3 *9 +2/3*(-15x) -2

-6x +6 -10x -2

Combine like terms

-6x-10x +6-2

-16x+4

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Precal help if you could could you answer both. Me finishing this helps me graduate.
oee [108]

Exercise 1:

The easiest way to compute powers of complex numbers is to write them in the form

z = \rho e^{i\theta} = \rho(\cos(\theta)+i\sin(\theta))

In this form, you have

z^n = \rho^n e^{in\theta} = \rho^n(\cos(n\theta)+i\sin(n\theta))

The magnitude of the number is given by

z=a+bi \implies \rho = \sqrt{a^2+b^2}

So, we have

z=-1+\sqrt{3}i \implies \rho = \sqrt{1+3}=2

As for the angle, we have

z=a+bi \implies \theta = \text{atan2}\dfrac{b}{a}

So, we have

z=-1+\sqrt{3}i \implies \theta = \text{atan2}\left(\dfrac{-\sqrt{3}}{-1}\right) = -\dfrac{2\pi}{3}

Finally,

z=-1-\sqrt{3}i = 2\left(\cos\left( -\dfrac{2\pi}{3}\right) + i\sin\left( -\dfrac{2\pi}{3}\right)\right) \implies z^6 = 2^6\left(\cos\left( -4\pi\right) + i\sin\left(-4\pi\right)\right) = 64

Exercise 2:

You simply have to compute the trigonometric function:

\cos\left(-\dfrac{\pi}{4}\right) = \dfrac{\sqrt{2}}{2},\quad \sin\left(-\dfrac{\pi}{4}\right) = -\dfrac{\sqrt{2}}{2}

So, we have

z = \sqrt{2}\left(\dfrac{\sqrt{2}}{2} - i\dfrac{\sqrt{2}}{2}\right) = 1-i

7 0
3 years ago
A​ 150-pound person uses 5.1 calories per minute when walking at a speed of 4 mph. How long must a person walk at this speed to
wolverine [178]

Let 't' represent the time of the walk in minutes.

5.1*t = 220

t = 43.14 min

The person needs to walk at least 43.14 minutes to but at least 220 calories.

6 0
3 years ago
How many solutions exist for the given equation? 3x(x - 2) = 22 - x
Mila [183]
The solution exist for the given equation are
x=-2
and
x=11/3
5 0
3 years ago
Someone please explain this question PART "b) i" ONLY!!!
Gnom [1K]
<h3>Answer:   (n-1)^2</h3>

This is because we have a list of perfect squares 0,1,4,9,...

We use n-1 in place of n because we're shifting things one spot to the left, since we start at 0 instead of 1.

In other words, if the answer was n^2, then the first term would be 1^2 = 1, the second term would be 2^2 = 4, and so on. But again, we started with 0^2 = 0, so that's why we need the n-1 shift.

You can confirm this is the case by plugging n = 1 into (n-1)^2 and you should find the result is 0^2 = 0. Similarly, if you tried n = 2, you should get 1^2 = 1, and so on. It appears you already wrote the answer when you wrote "Mark Scheme".

All of this only applies to sequence A.

side note: n is some positive whole number.

8 0
3 years ago
I am the number of red tiles in a design with red and blue tiles. The red tiles each have 3 sides. The blue tiles each have 5 si
nekit [7.7K]
If each blue tile has 5 sides and you know you have 3 blue tiles you can multiply 5 by 3
5 x 3 = 15 sides


Next you know the total number of sides is 30 and you just figured out that your 3 blue tiles have a total of 15 sides so you can subtract 15 from 30 to find how many sides are left
30 - 15 = 15sides

Since you know that these are not blue tiles because in the question it stated that you have 3 blue tiles. These have to be sides for red tiles.

Each red tile have 3 sides so you can divide 15 by 3
15/3 = 5

There are 5 red tiles
You are the number 5


8 0
3 years ago
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