Question

Write an equation for the nth term of the geometric sequence. Then find a sub 6

Answer 1

Answer:

$a_n = -192(\frac{-1}{4})^{n-1}$

$a_6= \frac{3}{16}$

Step-by-step explanation:

Explicit Formula: $a_n = a_1(r)^{n-1}$

Step 1: Find r

-192/48 = -4

So we are dividing -4 or multiplying -1/4

Step 2: Write explicit formula

$a_n = -192(\frac{-1}{4})^{n-1}$

Step 3: Find $a_6$

$a_6 = -192(\frac{-1}{4})^{6-1}$

$a_6= \frac{3}{16}$