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Akimi4 [234]
3 years ago
8

(-9z - 8) - (4z - 7)

Mathematics
1 answer:
inn [45]3 years ago
7 0
The answer is -13z - 1
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How do i do this problem
dezoksy [38]
X*y=y/b........................
7 0
3 years ago
Can someone please help me with these two questions! :( ill mark u as brainlest
Maslowich

Answer:

1.A by SSS axiom

2.F as angle A is 62*

4 0
3 years ago
How to show these 2 problems are inverses
nataly862011 [7]
\bf \begin{cases}
f(x)=\sqrt[3]{7x-2}\\\\
g(x)=\cfrac{x^3+2}{7}
\end{cases}\\\\
-----------------------------\\\\
now
\\\\
f[\ g(x)\ ]\implies f\left[ \frac{x^3+2}{7} \right]\implies \sqrt[3]{7\left[ \frac{x^3+2}{7} \right]-2}\implies \sqrt[3]{x^3+2-2}
\\\\\\
\sqrt[3]{x^3}\implies x\\\\
-----------------------------\\\\
or
\\\\
g[\ f(x)\ ]\implies g\left[\sqrt[3]{7x-2}\right]\implies \cfrac{\left[\sqrt[3]{7x-2}\right]^3+2}{7}
\\\\\\
\cfrac{7x-2+2}{7}\implies \cfrac{7x}{7}\implies x

thus f[ g(x) ] = x indeed, or g[ f(x) ] =x, thus they're indeed inverse of each other
8 0
3 years ago
Solve the following systems: 3x+4y=0 2x+3y=1
yanalaym [24]

Answer:

Answer is x= -4 and y= 3

Step-by-step explanation:

given \: equations \: are \\ 3x + 4y = 0 \:  \: and \: 2x + 3y = 1  \\ multiply \: by \: 2 \: in \: first \: equation \\ 6x + 8y = 0 \\ multiply \: by \: 3 \: in \: second \: equation \\ 6x + 9y = 3 \\ subtracting \: the \: above \: mentioned \: equation \:  \\  we \: get \:  - y =  - 3 \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  y = 3 \\ substitute \: y = 3 \: in \: first \: equation \\ 3x + 4(3) = 0 \\ 3x =  - 12 \\ x =  - 4

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

7 0
3 years ago
Which of the following is true of histograms? (CHECK ALL THAT APPLY .) AND EXPLAINE
Lubov Fominskaja [6]
Answer: B, C
These are correct.
4 0
2 years ago
Read 2 more answers
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