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3 years ago

14

Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar. Solve the equation

2/7=6x/4x+17

2 answers:

Furkat [3]3 years ago

8 0

Idk how to explain it but i got 1

Anastaziya [24]3 years ago

8 0

Answer:

1

Step-by-step explanation:

because 6*1=6 and 4*1=4 so it would be 6/4+17= 6/21 if u simplify it it'll = 2/7

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chu vi của một hình chữ nhật là 240 cm. Tính diện tích hình chữ nhật đó, biết tỉ số độ dài hai cạnh là 5 và 7

ch4aika [34]

(-) Tỉ số độ dài 2 cạnh là 5 và 7
=> Chiều rộng = 5:12, chiều dài = 7:12
(-) Chu vi = 240 suy ra tổng chiều dài + chiều rộng = 240 : 2 = 120
(-) Chiều rộng = 120 x 5 : 12 = 50
Chiều dài = 120 x 7 : 12 = 70
(-) Diện tích = 50 x 70 = 3500

4 0

3 years ago

In a class 27 of students, 12 have a cat and 11 have a dog. There are 5 students who have a cat and a dog. What is the probabili

frosja888 [35]

Answer:

41.67% probability that a student has a dog given that they have a cat

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: having a cat.

Event B: having a dog.

12 of 27 students have a cat:

This means that $P(A) = \frac{12}{27}$

5 students who have a cat and a dog.

This means that $P(A \cap B) = \frac{5}{27}$

What is the probability that a student has a dog given that they have a cat?

$P(B|A) = \frac{\frac{5}{27}}{\frac{12}{27}} = \frac{5}{12} = 0.4167$

41.67% probability that a student has a dog given that they have a cat

6 0

4 years ago

3x/2 = 5<br><br><br> What's x????

Anni [7]

$\frac{3x}{2} = 5$
taking 2 to the other side ⇒ $\frac{3x}{}$ = 5 x 2
3x=10
taking 3 to the other side ⇒ x = $\frac{10}{3}$
x = 3.34

3 0

4 years ago

Read 2 more answers

No links plz<br><br><br> x+1/ 3x^3 +10x^2-x-9

Irina-Kira [14]

Answer:

You didn't tell us much on what to do, so I just guessed you wanted it simplified. If you want a different answer, please do so tell me and I'll edit my answer to fit.

Simplified: 10 $x^{2}$ + $\frac{1}{3x^{3} }$ - 9

5 0

3 years ago

A major credit card company has determined that customers charge between $100 and $1100 per month. If the monthly amount charged

Alexxx [7]

Answer:

a) $E(X) = \frac{a+b}{2} = \frac{100+1100}{2}=600$

b) First we need to calculate the variance given by this formula:

$Var(X) = \frac{(b-a)^2}{12}= \frac{(1100-100)^2}{12} = 83333.33$

And the deviation would be:

$Sd(X) = \sqrt{83333.33}= 288.675$

c) $P(600 < X< 889) = P(X$

And using the cdf we got:

$P(600 < X< 889)= F(889) -F(600) = \frac{889-100}{1000} -\frac{600-100}{1000}= 0.789- 0.5= 0.289$

d) $P(311 < X< 889)= F(889) -F(311) = \frac{889-100}{1000} -\frac{311-100}{1000}= 0.789- 0.211= 0.578$

Step-by-step explanation:

For this case we define the random variable X who represent the customers charge, and the distribution for X on this case is:

$X \sim Unif (a= 100, b=1100)$

Part a

For this case the average is given by the expected value and we can use the following formula:

$E(X) = \frac{a+b}{2} = \frac{100+1100}{2}=600$

Part b

First we need to calculate the variance given by this formula:

$Var(X) = \frac{(b-a)^2}{12}= \frac{(1100-100)^2}{12} = 83333.33$

And the deviation would be:

$Sd(X) = \sqrt{83333.33}= 288.675$

Part c

For this case we want to find the percent between 600 and 889, so we can use the cumulative distribution function given by:

$F(x) = \frac{X -100}{1100-100}= \frac{x-100}{1000}, 100 \leq X \leq 1100$

And we can find this probability:

$P(600 < X< 889) = P(X$

And using the cdf we got:

$P(600 < X< 889)= F(889) -F(600) = \frac{889-100}{1000} -\frac{600-100}{1000}= 0.789- 0.5= 0.289$

Part d

$P(311 < X< 889) = P(X$

And using the cdf we got:

$P(311 < X< 889)= F(889) -F(311) = \frac{889-100}{1000} -\frac{311-100}{1000}= 0.789- 0.211= 0.578$

6 0

3 years ago