X=2y
2x+5y=9
substitute the x=2y into the second equation
2(2y)+5y=9
multiple the 2y by 2. 4y+5y=9
combine like terms. 9y=9
divide the 9 out from both sides. y=1
plug the y back into the first equation
x=2(1)
multiply. x=2
your answer is: x=2
y=1
What is the answer choices bc I can’t help if I don’t know them
Answer:
6 feet.
Step-by-step explanation:
Dimensions of the Pool =80 feet long by 20 feet wide
Area of the walkway =1344 square feet.
If the width of the walkway=w
- Length of the Larger Rectangle =80+2w
- Width of the Larger Rectangle =20+2w
Area of the Walkway =Area of the Larger Rectangle - Area of the Pool
Answer:
use logarithms
Step-by-step explanation:
Taking the logarithm of an expression with a variable in the exponent makes the exponent become a coefficient of the logarithm of the base.
__
You will note that this approach works well enough for ...
a^(x+3) = b^(x-6) . . . . . . . . . . . variables in the exponents
(x+3)log(a) = (x-6)log(b) . . . . . a linear equation after taking logs
but doesn't do anything to help you solve ...
x +3 = b^(x -6)
There is no algebraic way to solve equations that are a mix of polynomial and exponential functions.
__
Some functions have been defined to help in certain situations. For example, the "product log" function (or its inverse) can be used to solve a certain class of equations with variables in the exponent. However, these functions and their use are not normally studied in algebra courses.
In any event, I find a graphing calculator to be an extremely useful tool for solving exponential equations.
The answer is A. sin40=6/x
