<span>the limit as x approaches -3 of [g(x)-g(-3)]over(x+3) is the same as the derivative, or slope, of g(x) at the point x=-3, or g'(-3).
Since you are given the equation of the tangent line, the answer is just the slope of that line.
</span><span>2y+3=-(2/3)(x-3)
</span><span>6y+9=-2(x-3)
6y+9=-2x+6
6y=-2x-3
y= (-2x-3)/6
slope is -2/6 = </span>
Answer:
y = 13x
Step-by-step explanation:
gradient = 13
x = 0
y = 0
so
= 13
cross multiply and you get
y = 13x
u need to finish 4 assignments in 1 hour
The answer to this question is -10