8 39/40
=8+39/40
=8•40/40+39/40
=320/40+39/40
=320+39/40
=359/40
=8.975
The answer is 8 39/40=8.975
<u>Given</u>:
The given equation is ![q+\log _{2}(6)=2 q+2](https://tex.z-dn.net/?f=q%2B%5Clog%20_%7B2%7D%286%29%3D2%20q%2B2)
We need to determine the approximate value of q.
<u>Value of q:</u>
To determine the value of q, let us solve the equation for q.
Hence, Subtracting
on both sides of the equation, we get;
![q=2 q+2-\log _{2}(6)](https://tex.z-dn.net/?f=q%3D2%20q%2B2-%5Clog%20_%7B2%7D%286%29)
Subtracting both sides of the equation by 2q, we have;
![-q=2-\log _{2}(6)](https://tex.z-dn.net/?f=-q%3D2-%5Clog%20_%7B2%7D%286%29)
Dividing both sides of the equation by -1, we have;
![q=\log _{2}(6)-2](https://tex.z-dn.net/?f=q%3D%5Clog%20_%7B2%7D%286%29-2)
Now, substituting the value of
, we have;
![q=2.585-2](https://tex.z-dn.net/?f=q%3D2.585-2)
Subtracting the values, we get;
![q=0.585](https://tex.z-dn.net/?f=q%3D0.585)
Thus, the approximate value of q is 0.585
Hence, Option C is the correct answer.
Answer:
The single decimal multiplier used to increase by 18% followed by a 12% decrease is 0.21.
Step-by-step explanation:
Let 'x' be the number
As first the number has to be increased by 18%
so
Step 1: write the percentage '18%' in decimal form
18% = 0.18
Step 2: For percentage increases: add the decimal to 1
1 + 0.18 = 1.18
Step 3: Multiply the number x by the multiplier, found in Step 2
x × 1.18 = 1.18x
<u><em>NEXT WE HAVE TO DECREASE 1.18x by 12%</em></u>
Apply the same method but with a number 1.18x
- Write the percentage '12%' in decimal form
12% = 0.12
- For percentage decreases: subtract the decimal to 1
1 - 0.18 = 0.18
- Multiply the number 1.18x by the multiplier, found in Previous step
1.18x × 0.18 = 0.21x
Therefore, the single decimal multiplier used to increase by 18% followed by a 12% decrease is 0.21.
Answer:
The first answer is correct I believe
Step-by-step explanation:
The answer to the question is 12