Answer:
Say that the shape is a parallelogram with equal length sides;
AB = CD
ABD = CDB as the bisecting lines (you have drawn) prove ABD : CDB are both isosceles triangles.
Therefore ABD = ADB
Draw the shape's diagonals as each others' perpendicular bisectors;
Draw the shape's diagonals bisect both pairs of opposite angles.
If two non congruent angles were given in example 70 degree and 110 degree then say M ∴ = (1/2 )(M∴BAD) = 35 = (1/2 )(M∴BEF) = 35
and do the same for 1/2(M∴ABC) = 55 = 1/2 (M∴CDA) = 55
If angle D is congruent to angle E, then the triangle DFE is an isosceles triangle (look at the picture).
Therefore DF ≅ EF.
DE = x + 4, EF = 4x - 8, DF = 7x - 35
The equation:
7x - 35 = 4x - 8 <em>add 35 to both sides</em>
7x = 4x + 27 <em>subtract 4x from both sides</em>
3x = 27 <em>divide both sides by 3</em>
x = 9
DE = x + 4 → DE = 9 + 4 = 13
EF = 4x - 8 → EF = 4(9) - 8 = 36 - 8 = 28
DF = 7x - 35 → DF = 7(9) - 35 = 63 - 35 = 28
<h3>Answer:</h3><h3>x = 9, DE = 13, EF = 28, DF = 28.</h3>
Answer:
60⁰ hope I'm right
Step-by-step explanation:
I think
Q1,
A)30 : 3
B)300:3
Q2
A)x=35
B)x=12
Q3
5
2 and -16 are 2 factors that add up to -14