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soldi70 [24.7K]
3 years ago
12

A movie theater has 7 rows of 20 seats. Each row has 5 seats that are reserved for annual pass holders. How many seats are not r

eserved for annual pass holders?
Mathematics
2 answers:
Nataly [62]3 years ago
8 0

The answer is 105.

To find this we know that there a 7 rows of 20 seats (7 times 20) or 140 seats.

We also know that each row have 5 reserved seats (5*7) or 35 seats.

Now all we have to do is subtract. 140 - 35 = 105

poizon [28]3 years ago
3 0

Answer:

<em>105.</em>

<em />

Step-by-step explanation:

7rows × 20seats = <em>140seats total</em>

7rows × 5seats = <em>35seats reserved</em>

140total - 35reserved = 105open

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3 years ago
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14x+7y=217 <br> 14x+3y=189
kondor19780726 [428]

Answer:

y = 7

x = 12

Step-by-step explanation:

14x+7y=217, then 14x = 217 - 7y

14x+3y=189, then 14x = 189 - 3y

217 - 7y = 189 - 3y

add 7y to each side of the equation:

4y + 189 = 217

subtract 1890 from each side:

4y = 28

divide both sides by 4:

y = 7

14x + 3(7) = 189

subtract 21 from each side:

14x = 168

divide both sides by 14:

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3 years ago
Consider the function below. (If an answer does not exist, enter DNE.) f(x) = x3 − 27x + 3 (a) Find the interval of increase. (E
xxTIMURxx [149]

Answer:

(-∞,-3) and (3,∞)  

Step-by-step explanation:

f(x) = x³ − 27x + 3

1. Find the critical points

(a) Calculate the first derivative of the function.

f'(x) = 3x² -27  

(b) Factor the first derivative

f'(x)= 3(x² - 9) = 3(x + 3) (x - 3)

(c) Find the zeros

3(x + 3) (x - 3) = 0

x + 3 = 0      x - 3 = 0

     x = -3          x = 3

The critical points are at <em>x = -3</em> and x = 3.

2. Find the local extrema

(a) x = -3

f(x) = x³ − 27x + 3 = (-3)³ - 27(-3) + 3 = -27 +81 + 3 = 57

(b) x = 3

f(x) = x³ − 27x + 3 = 3³ - 27(3) + 3 = 27 - 81 + 3 = -51

The local extrema are at (-3,57) and (3,-51).

3, Identify the local extrema as maxima or minima

Test the first derivative (the slope) over the intervals (-∞, -3), (-3,3), (3,∞)

f'(-4) = 3x² -27 = 3(4)² - 27  = 21

f'(0) = 3(0)² -27 = -27

f'(4) = 3(4)² - 27 = 51

The function is increasing on the intervals (-∞,-3) and (3,∞).

The graph below shows the critical points of your function.

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4. Two cylinders have dimensions in the ratio of 2:3. The smaller cylinder has a surface area of 16 cm.
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