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Snezhnost [94]
2 years ago
11

Solve for the values of x in the equation: 2^(x) = 4x.

Mathematics
2 answers:
Eva8 [605]2 years ago
7 0

There are two of them. 

I don't know a mechanical way to 'solve' for them.

One can be found by trial and error:

x=0 . . . . . 2^0 = 1 . . . . . 4(0) = 0 . . . . . no, that doesn't work
x=1 . . . . . 2^1 = 2 . . . . . 4(1) = 4 . . . . . no, that doesn't work
x=2 . . . . . 2^2 = 4 . . . . . 4(2) = 8 . . . . . no, that doesn't work
x=3 . . . . . 2^3 = 8 . . . . . 4(3) = 12 . . . . no, that doesn't work
<em>x=4</em> . . . . . 2^4 = <em><u>16</u></em> . . . . 4(4) = <em><u>16</u></em> . . . . Yes !  That works !       yay !

For the other one, I constructed tables of values for 2^x and (4x)
in a spread sheet, then graphed them, and looked for the point
where the graphs of the two expressions cross.

The point is near, but not exactly,         <em>x = 0.30990693...

</em>
If there's a way to find an analytical expression for the value, it must involve
some esoteric kind of math operations that I didn't learn in high school or
engineering school, and which has thus far eluded me during my lengthy
residency in the college of hard knocks.<em> </em> If anybody out there has it, I'm
waiting with all ears.<em>

</em>
Andreyy892 years ago
4 0
2^{x} = 4x \\ln(2^{x}) = ln(4x) \\\frac{xln(2)}{ln(2)} = \frac{ln(4x)}{ln(2)} \\x = 4
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Solve the equations.<br> a. (x − 2)^2 = 9<br> b. 3(x − 2)^2 = 9<br> c. 6 = 24(x + 1)^2
seropon [69]

Answer: a) x = 5 or -1 b) x = √3+2

c) x = -1/2 or -3/2

Step-by-step explanation:

a) (x − 2)² = 9

First step is to take the square root of both sides to eliminate the square

√ (x − 2)² = √9

x-2 = +-3

x = +3+2

x = 5 and;

x = -3+2

x = -1

x = 5 or -1

b) 3(x-2)² = 9

First we divide both sides by 3 to get;

(x-2)² = 9/3

(x-2)² = 3

Second step is to take the square root of both sides to eliminate the square

√(x-2)² = √3

x-2 = √3

x = √3+2

c) 6 = 24(x+1)²

Dividing both sides by 24, we have

6/24 = (x+1)²

1/4 = (x+1)²

Taking the square root of both sides we have

√1/4 = √(x+1)²

= +-1/2 = x+1

x = +1/2-1 = -1/2 and;

x = -1/2-1 = -3/2

x = -1/2 or -3/2

4 0
3 years ago
Simplify the expression cos x cot x+ sin x please select the best answer from the choices provided a.0, b.csc x, c. Tan x, d sec
expeople1 [14]

Answer:

cot x = \frac{cos x}{sin x}

cos x \frac{cos x}{sin x} + sin x

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Solving for cos^2 x we got cos^2 x =1 -sin^2 x and replacing this we got:

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And then the best option for this case would be:

b.csc x

Step-by-step explanation:

For this case we have the following expression given:

cos x cot x + sin x

We know from math properties that the definition for cot is cot x = \frac{cos x}{sin x}

If we use this definition we got:

cos x \frac{cos x}{sin x} + sin x

\frac{cos^2 x}{sin x} +sin x

Now we can use the following identity:

sin^2 x + cos^2 x =1

Solving for cos^2 x we got cos^2 x =1 -sin^2 x and replacing this we got:

\frac{1-sin^2 x}{sin x} +sin x

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4 0
3 years ago
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faltersainse [42]

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Step-by-step explanation:

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Schach [20]

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Step-by-step explanation:

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3 years ago
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olchik [2.2K]

\huge\text{Hey there!}

\huge\textbf{Question reads....}

\large\text{Which expression is equivalent to 2(x - 1) + x?}

\huge\textbf{Step by step to find your result}

\large\textbf{First you have to DISTRIBUTE 2 WITHIN the}\\\large\textbf{PARENTHESES}

\large\text{2(x - 1) + x}\\\rightarrow\large\text{2(x) + 2(-1) + x}\\\rightarrow\large\text{2x - 2 + x}\\\rightarrow\large\text{2x - 2 + 1x}\\\rightarrow\large\textbf{COMBINE the LIKE TERMS}\leftarrow\\\rightarrow\large\text{(2x + 1x) - (2)}\\\rightarrow\large\text{3x - 2}

\huge\textbf{FINALLY WE HAVE YOUR RESULT}

\huge\boxed{\textsf{Therefore, your answer is: }}}\\\huge\boxed{\mathsf{Option\ B. \ 3x - 2}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy }\\\huge\text{your day!}

<h2>~\frak{Amphitrite1040:)}</h2>
5 0
2 years ago
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