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Talja [164]
3 years ago
9

Find each measure of the parallelogram

Mathematics
1 answer:
zysi [14]3 years ago
5 0

Answer:

z = 8

x = 5

Step-by-step explanation:

Because it is a parrallelogram 3z - 4 and 2z + 4 is congruent if you make it an equation and equal each other (3z - 4 = 2z + 4) It will be 8

They are also equal to each other so you will do the same thing

4x - 6 = x + 9

x = 5

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Dunkin Donuts makes its doughnuts for $2.00 each. DD wnats a 50% markup on the
vesna_86 [32]

Answer:
Cost of each donut should be $3.00

Step-by-step explanation:

please tell me if I am wrong. 2.00 x 0.5 is 1. 2 + 1 is 3.

8 0
2 years ago
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What is the pressure in atmospheres exerted by a 0.500 mole sample of nitrogen gas in a 10.0 L container at 25.0°C?
drek231 [11]

Answer:

1.2218 atm

Step-by-step explanation:

From ideal gas formula,

PV=nRT

Where n= number of moles

V= volume

T= temperature=25.0°C

= (273 + 25) = 298 K

R= gas constant = 0.082 l atm /K mol.

Making P subject of formula we have

P= [nRT] /V

Then substitute the values we have

P= [0.5 x 0.082 x 298] / 10

P= 1.2218 atm

6 0
3 years ago
I will give you a brainlists if u answere correct what is 59267+1726548=?
erik [133]

Answer:

The answer is 1,785,815

6 0
3 years ago
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Which equation has infinitely many solutions?
Snezhnost [94]

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4 0
3 years ago
Find the distance, in feet, a particle travels in its first 2 seconds of travel, if it moves according to the velocity equation
just olya [345]

Answer:

The particle will travel 6 feet in first 2 seconds.

Step-by-step explanation:

We have been given that a particle moves according to the velocity equation v(t)= 6t^2-18t+12. We are asked to find the distance that the particle will travel in its first 2 seconds.

s(t)=\int |v(t)|dt

s(t)=\int\limits^2_0 |6t^2-18t+12|dt

Now, we will eliminate the absolute value sign as:

s(t)=\int\limits^1_0 6t^2-18t+12dt+\int\limits^2_1 -6t^2+18t-12dt

s(t)=[\frac{6t^3}{3}-\frac{18t^2}{2}+12t]^1_0 +[\frac{-6t^3}{3}+\frac{18t^2}{2}-12t]^2_1

s(t)=[2t^3-9t^2+12t]^1_0 +[-2t^3+9t^2-12t]^2_1

s(2)=2(1)^3-9(1)^2+12(1)-(2(0)^3-9(0)^2+12(0))-2(2)^3+9(2)^2-12(2)-(-2(1)^3+9(1)^2-12(1))

s(2)=2-9+12-(0)-16+36-24-(-2+9-12)

s(2)=5-(0)-4-(-5)

s(2)=5-4+5

s(2)=6

Therefore, the particle will travel 6 feet in first 2 seconds.

   

 

7 0
2 years ago
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