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Mila [183]
2 years ago
14

1/3 is greater than what other fractions

Mathematics
2 answers:
Novosadov [1.4K]2 years ago
7 0
As 1/3 = 2/6 = 3/9 = 4/12

and 2/6 is greater than 1/6
    3/9 is greater than 2/9
     etc..

So

1/3 is greater than 1/6 ; 2/9 ; ...
SashulF [63]2 years ago
3 0
Countless. It's greater than 1/4, 1/5, 1/6, 1/7, 2/7, 1/8, 1/9, 2/9. The list goes on and on my friend/
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How to get answer for number 1: | 4+2i |

\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=4,\:b=2\\=\sqrt{4^2+2^2}\\Refine\\=\sqrt{20}\\\sqrt{20}=2\sqrt{5}\\=2\sqrt{5}

How to get answer for number 2: | 5-i |

\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=5,\:b=-1\\=\sqrt{5^2+\left(-1\right)^2}\\=\sqrt{26}

Number 3 how to get answer: | -3i |

\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=0,\:b=-3\\=\sqrt{0^2+\left(-3\right)^2}\\Refine\\=\sqrt{9}\\\sqrt{9}\\\mathrm{Factor\:the\:number:\:}\:9=3^2\\=\sqrt{3^2}\\\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^n}=a\\\sqrt{3^2}=3\\= 3

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Combine the results:

\boxed{2m^5\cdot 5m^3\cdot 7m^2=70\cdot m^{10}}

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