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defon
4 years ago
14

What do you add to 3 5/7 to make 7

Mathematics
2 answers:
s344n2d4d5 [400]4 years ago
8 0
You add 3 2/7. 7/1-3 5/7= 3 2/7
Arisa [49]4 years ago
3 0
I think 3 2/7 is the correct answer.


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If 2x -3(x+4)=-5, Then x=​
kherson [118]
The answer is -7

2x-3(x+4)=-5

Multiply by -3

2x-3x-12=-5

Collect like terms

-x-12=-5

Move constant to the right to change its sign

-x=-5+12

Add

-x=7

Change the signs

x=-7

3 0
3 years ago
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Mrs. Sing bought a pound of green beans for $1.80. How much will Mrs. Tennison pay for 3 and 1/2 pounds of green beans?
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Mrs. sing will pay 6,30$ for 3 and 1/2 pounds of green beans

8 0
3 years ago
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Check my answer?
Effectus [21]
D = 2r => 12.6 = 2*r => r=6.3
A = π*r^2 = (3.14) * (6.3)^2 = (3.14)*(39.69) = 124.6266 which is approximately 124.63

Hope this helps!
6 0
3 years ago
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There are (10 to the 8 power)to the 2 power ⋅ 10 to the 0 power candies in a store. What is the total number of candies in the s
Rashid [163]

(10^8)^2\cdot10^0=10^{16}\cdot1=10^{16}=10,000,000,000,000,000

4 0
4 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
astra-53 [7]

Answer:

3\pi \rightarrow y=2\cos \dfrac{2x}{3}\\ \\\dfrac{2\pi }{3}\rightarrow y=6\sin 3x\\ \\\dfrac{\pi }{3}\rightarrow  y=-3\tan 3x\\ \\10\pi \rightarrow y=-\dfrac{2}{3}\sec \dfrac{x}{5}

Step-by-step explanation:

The period of the functions y=a\cos(bx+c) , y=a\sin(bx+c), y=a\sec (bx+c) or y=a\csc(bx+c) can be calculated as

T=\dfrac{2\pi}{b}

The period of the functions y=a\tan(bx+c) or y=a\cot(bx+c) can be calculated as

T=\dfrac{\pi}{b}

A. The period of the function y=-3\tan 3x is

T=\dfrac{\pi}{3}

B. The period of the function y=6\sin 3x is

T=\dfrac{2\pi}{3}

C. The period of the function y=-4\cot \dfrac{x}{4} is

T=\dfrac{\pi}{\frac{1}{4}}=4\pi

D. The period of the function y=2\cos \dfrac{2x}{3} is

T=\dfrac{2\pi}{\frac{2}{3}}=3\pi

E. The period of the function y=-\dfrac{2}{3}\sec \dfrac{x}{5} is

T=\dfrac{2\pi}{\frac{1}{5}}=10\pi

5 0
4 years ago
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