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laiz [17]
3 years ago
13

1/2(logx4+logxy)-3logxz

Mathematics
1 answer:
Sphinxa [80]3 years ago
3 0
\bf log_{{  a}}(xy)\implies log_{{  a}}(x)+log_{{  a}}(y)
\\ \quad \\
% Logarithm of rationals
log_{{  a}}\left(  \frac{x}{y}\right)\implies log_{{  a}}(x)-log_{{  a}}(y)
\\ \quad \\
% Logarithm of exponentials
log_{{  a}}\left( x^{{  b}} \right)\implies {{  b}}\cdot  log_{{  a}}(x)\qquad 
and\qquad a^{\frac{{ n}}{{ m}}} \implies  \sqrt[{ m}]{a^{ n}}\\\\
-----------------------------\\\\

\bf \cfrac{1}{2}\left[ log_x(4)+log_x(y) \right]-3log_x(z)
\\\\\\
\cfrac{1}{2}\left[ log_x(4\cdot y) \right]-3log_x(z)\implies log_x\left[ (4y)^{\frac{1}{2}} \right]-log_x(z^3)
\\\\\\
log_x\left[ \cfrac{(4y)^{\frac{1}{2}}}{z^3} \right]\implies log_x\left[ \cfrac{\sqrt{4y}}{z^3} \right]
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