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Naya [18.7K]
3 years ago
14

I need you to help me solve his

Mathematics
2 answers:
klio [65]3 years ago
7 0
2, 4, 10, and 18. These aren't the only answers but they all work
TiliK225 [7]3 years ago
5 0
6, 9, 12, 15. All you need to find is multiples of 3.
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Plz Help ASAP<br>plz help me with #2. <br>Plz I'm begging u!!!!!!
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$230 divided by 1/4 = 57.5
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How do u find this area??
alexandr1967 [171]

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Robert wears a suit o work every day. In his closet, he has 3 blazers, 5 button-up shirts, 12 bow ties, 6 pairs of pants, and 3
mars1129 [50]

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3 years ago
A pumpkin is launched from the top of a 20 foot tall platform at an initial velocity of 84 feet per second. The height, h, of th
Gennadij [26K]
<h2>Explanation:</h2>

In this problem we have a pumpkin is launched from the top of a 20 foot tall platform at an initial velocity of 84 feet per second. So the height, h, of the pumpkin at time t seconds after the launch can be modeled by the equation:

h(t) = -16t^2 + 84t + 20

So this is the equation of a parabola. The maximum of this parabola occurs at its vertex. So let's find this vertex:

\text{The x-value of the vertex is}: \\ \\ t=-\frac{b}{2a} \\ \\ \\ Where: \\ \\ a=-16 \\ \\ b=84 \\ \\ c=20 \\ \\ \\ t=-\frac{84}{2(-16)} \\ \\ t=-\frac{84}{-32} \\ \\ t=\frac{21}{8}=2.625 \\ \\ h(2.625)=-16(2.625)^2+84(2.625)+20 \\ \\ h(2.625)=-110.25+220.5+20 \\ \\ h(2.625)=130.25m

Finally, the maximum occurs at time 2.625 seconds when the height is 130.25m

8 0
3 years ago
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