2over7 wat would be it's improper fraction

1 answer:

5 0

In order for it to be an improper fraction there has to be a larger number on the numerator. For instance 17/8 is improper

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Use basic trigonometric identities to simplify the expression: sin (-x) cos (-x) csc (-x) =?

Anestetic [448]

Answer:

$sin (-x) cos (-x) csc (-x) =cos(x)$

Step-by-step explanation:

We know by definition that the cosine is an even function, therefore

$cos (-x) = cos (x)$

We also know that the sin is an odd function, therefore

$sin (-x) = -sin (x)$

By definition:

$cscx = \frac{1}{sinx}.$

Then:

$csc(-x) = \frac{1}{sin(-x)}.$

$csc(-x) = -\frac{1}{sin(x)}.$

Using these trigonometric properties we can simplify the expression

$sin (-x) cos (-x) csc (-x)= -sin(x)cos(x)*(-\frac{1}{sin(x)})\\\\sin (-x) cos (-x) csc (-x)=cos(x)$

7 0

3 years ago

Read 2 more answers

What is the answer to question 10

Whitepunk [10]

He needs to earn ; 77.99-20= 57.99 dollars

so in one week there are 2 weekends; so he earns 6×3×2 = 36 dollars

so no of week = 57.99÷ 36= 1.6 weeks

so weeks are in natural no thus it will take him 2 weeks !!

8 0

2 years ago

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Please solve the problem

jek_recluse [69]

Treat the matrices on the right side of each equation like you would a constant.

Let 2X + Y = A and 3X - 4Y = B.

Then you can eliminate Y by taking the sum

4A + B = 4 (2X + Y) + (3X - 4Y) = 11X

==> X = (4A + B)/11

Similarly, you can eliminate X by using

-3A + 2B = -3 (2X + Y) + 2 (3X - 4Y) = -11Y

==> Y = (3A - 2B)/11

It follows that

$X=\dfrac4{11}\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\dfrac1{11}\begin{bmatrix}7&-10\\-7&11\end{bmatrix} \\\\ X=\dfrac1{11}\left(4\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\left(\begin{bmatrix}48&-12\\40&88\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\begin{bmatrix}55&-22\\33&99\end{bmatrix} \\\\ X=\begin{bmatrix}5&-2\\3&9\end{bmatrix}$