1. 160 2. 520 3.240 hopefully they are right
Answer:
V = ∫∫∫rdrdθdz integrating from z = 2 to z = 4, r = 0 to √(16 - z²) and θ = 0 to 2π
Step-by-step explanation:
Since we have the radius of the sphere R = 4, we have R² = r² + z² where r = radius of cylinder in z-plane and z = height² of cylinder.
So, r = √(R² - z²)
r = √(4² - z²)
r = √(16 - z²)
Since the region is above the plane z = 2, we integrate z from z = 2 to z = R = 4
Our volume integral in cylindrical coordinates is thus
V = ∫∫∫rdrdθdz integrating from z = 2 to z = 4, r = 0 to √(16 - z²) and θ = 0 to 2π
The given triangles are similar by ~
Answer:
-6/5
Step-by-step explanation:
slope =coefficient of x
Answer:
yes, the given relation is a function.
Step-by-step explanation:
The given relation is
{(–3, –2), (–1, 0), (1, 0), (5, –2)}
A relation is called function if each element of the domain is paired with exactly one element of the range.
It means for each value of x there exist a unique value of y.
In the given relation for each value of x there exist a unique value of y.
Therefore the required solution is yes and this relation is a function.
